ITT we determine who should get to reproduce to gift the world with intelligent...

Joshua Edwards
Joshua Edwards

ITT we determine who should get to reproduce to gift the world with intelligent offspring

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Other urls found in this thread:

en.wikipedia.org/wiki/Bertrand's_box_paradox

Andrew Martinez
Andrew Martinez

%50 or 1/2? Organalizaon

Asher Moore
Asher Moore

50%
I studied maths at uni so I guess I have an unfair advantage, I'm socially retarded.

Andrew Lopez
Andrew Lopez

50% since one box is already ruled out

Aiden Ortiz
Aiden Ortiz

50% as only two of the boxes were eligible to have gold balls. You know it's not the one that had silver.

Brody Nelson
Brody Nelson

congrats, you're better than most of the people in the last one i made on /pol/. have a girl.

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Camden Williams
Camden Williams

but I answered wrong on purpose as bait >:(

Ayden Taylor
Ayden Taylor

You fuck. I know what you're doing. This problem is very similar to the flipping two coins and one lands heads problem but the answer is 50% which is the incorrect answer for the coins one. So people that think the answer to the coins one is 50% will use this to prove that they're right because they think it's the same problem.

Ryder Campbell
Ryder Campbell

bitch i dont care im already running like a nigger from the police to sell that gold ball

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Liam Rogers
Liam Rogers

well it's dicky snippy time for you then, no brainlets allowed in the new world, sorry user :(

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Adam Gomez
Adam Gomez

I know if you pick a box then take a ball out and it's gold; it is more likely that you picked the box with 2 gold balls than the box with only one gold ball.

It's less likely for you to produce a gold ball from box 2 than box 1, as box 2 has only 1 gold ball. So in all likelihood if the ball you took out from your chosen box was gold, you most likely have box 1

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Luke Perez
Luke Perez

Stop posting these bullshit questions, OP.

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Jonathan Gomez
Jonathan Gomez

but the answer is 2/3 you faggot
en.wikipedia.org/wiki/Bertrand's_box_paradox

Daniel Morris
Daniel Morris

Two thirds
Origogogog

Jace Cooper
Jace Cooper

seething shill, absolutely cringe and bluepilled. certain never to reproduce.

Christian Brooks
Christian Brooks

I would carry each of the boxes on an vector angle to both balls accumulate on each other.
The heavier one is gold.
Gold is heavier than silver this is the correct
answer. I would notably tell the difference between the only silver containing one vs the only gold containing one.

I know I can reproduce, i even have good genes actractivve for females I been told by them everything im just not interested in life what so ever and im sure everything happening in the world is leading me to despair which leads me to death i feel as if i were in an eternal hell and i hate myself deeply i really dread everything that is and i cannot win against that sorrow/hatred

im doing my life out of compromise, its better if i just leave all this up the planet is ruined and not turning back anyway

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Logan Garcia
Logan Garcia

oh brother...

originallyy

Xavier Gutierrez
Xavier Gutierrez

some guy and Wikipedia said a thing is right
Wowie zowie

Andrew Flores
Andrew Flores

50% right? Or is there something I'm missing?

Jordan King
Jordan King

Who said they'd let you feel the balls you fucking homo? Lead injection the moment you change your mind

Wyatt Parker
Wyatt Parker

ITT: brainlets don't understand the concept of conditional probability

Jackson Russell
Jackson Russell

Yeah, a brain. It's 2/3 because two of the three gold balls have another gold ball in the same box. It's that simple.

Get a refund on that degree

Parker Gray
Parker Gray

He's right
This shows the difference between simplified highschool probability classes and actual university probability theorems.
Its more probable that you chose the first box since it has the most gold balls, and if that's the case then you'll always get a gold ball on the next try.
Oh boy

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Christian Myers
Christian Myers

I don't understand? Please someone explain this to me, I'm horrible at maths.

I thought that the fact that I got a golden ball means that it can't be box 3 so I either picked from 1 or 2 in which case there can only be either 1 gold or 1 silver ball remaining meaning my chances are 1/2? I don't understand how it can be 2/3, sorry for being stupid.

Aaron Garcia
Aaron Garcia

physically i can feel each of the boxes weight im just not allowed to open them. this is the simple solution, feeling the weight.

unless mr thrickster puts hevier pieves of silver. than that of gold. which case i would make silver pointed arrows and kill the le happy merchant for tricking me and take his gold by force.

Matthew Diaz
Matthew Diaz

Label the balls as gold 123 and silver 123. Picking Gold 1 and Gold 2 are different events even though they're in the same box.

Camden Diaz
Camden Diaz

Reframe the question: if you have picked a gold ball, what is the probability that it came from the box with 2 gold balls rather than the one with only 1 gold ball?

Samuel Gray
Samuel Gray

When you pull out a gold ball, it's twice as likely to have come from the first box because there were two gold balls in it. If this isn't intuitive to you think about it like this: Imagine there are three boxes,
Box 1: 100 gold, 0 silver
Box 2: 1 gold, 99 silver
Box 3: 0 gold, 100 silver
You pick a box at random and pick a ball blindly and it happens to be gold. Isn't it much more likely to have come from box 1? Therefore, isn't it much more likely that the other balls in the same box as your ball are gold?

Austin Barnes
Austin Barnes

This. The ball you pick can either be g1, g2, g3, and two of those results give you another gold ball after. 2/3rds.

Kevin Parker
Kevin Parker

fuck off with ur intuitive bullshit bitch. Next you're gonna explain the monty hall by saying "doesn't it just feeeeeel like you got a goat??

Grayson Reed
Grayson Reed

What are some other brainlet filter questions?

Logan Scott
Logan Scott

Probability of getting a gold ball in of itself: 2 gold balls, 5 balls total. 2/5 odds.

Probability of the other ball being gold: only one box had two gold balls. There are three boxes. 1/3 odds.

Probability of taking one gold ball the first time: 6 balls, 3 gold of which are gold. 1/2 odds.

Probability of picking gold the first time and the other ball being gold: Product of two previous probabilities - 1/3*1/2= 1/6 odds.

Juan Cooper
Juan Cooper

i have one.

What are some other brainlet filter questions?

anyone who asks this is a guaranteed brainlet.

Asher Edwards
Asher Edwards

Pick any positive integer n. If n is even, divide it by 2. If n is odd, multiply it by 3 and add 1. Prove that repeating this process will always eventually get you down to 1.

If you can't solve this you're literally retarded

Liam Morris
Liam Morris

bro what the fuck are you even saying
you're not stipulating a problem
frame your shit correctly

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Carson Hernandez
Carson Hernandez

Imagine not understanding what conditional probability is

Jaxon Lewis
Jaxon Lewis

I have discovered a truly marvelous proof of this, but this post to narrow to contain it.

Andrew Turner
Andrew Turner

Thanks a lot, I get it now.

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Justin Powell
Justin Powell

If you can't even comprehend the question you're an even bigger brainlet than someone who gives the wrong answer

Dylan Walker
Dylan Walker

fuck of pierre

Chase Lewis
Chase Lewis

ignoring givens to over complicate the problem
first gold ball has already happened. Now, looking at the boxes, all we know is that the ball can be gold in the leftmost box or silver in the middle box. That's it. That's the whole problem lmao. Not your fault I have a massive, almost uncomfortably large brain though desu.

Chase Russell
Chase Russell

pick n
if n is even divide by 2
if n is odd multiply by 3 and add 1
prove it equals 1
guess that explains why you're here

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Anthony Moore
Anthony Moore

look up the monty hall problem to feel like a brainlet again.

Eli Diaz
Eli Diaz

2/3, the first gold ball can be any of the three.

Isaiah Sanders
Isaiah Sanders

66.6 recurring you tards

Jacob Russell
Jacob Russell

Holy shit you really are that fucking stupid

Charles Brooks
Charles Brooks

Retards. If you picked a gold ball that means you're in the middle or left box, the right box has no gold so it can only be middle or left. Given as you can only draw a gold or silver at that point, its a 50% chance. The right box never mattered it existed to draw attention to IQlets like you, especially the stupid fuck, you absolute arrogant cockbag calling othet people tards while falling for the most obvious fucking shit ever. You deserve to have your dick straight up obliterated with an orbital cannon, your genes are as useless as a perforated condom

Blake Phillips
Blake Phillips

If you drew a gold ball at first, you are twice as likely to be in box with 2 gold balls than the box with only 1 gold ball. It's a very simple experiment to do, and if you perform it, you will see that the right answer is 2/3.

Blake Collins
Blake Collins

I'm not going to bother to give a serious reply to bait, so just have this (You) instead.

Carson Lee
Carson Lee

is this bait or just dunning-kruger

Mason Richardson
Mason Richardson

Thats not how it works whatsoever. If you drew a gold ball, there are only 2 more options, drawing another gold, or a silver. You're looking at some initial percentage bullshit and thats not the case. Once a gold is drawn, only 2 options are left, a silver, or a gold, so its a 50/50 chance.
See above. OP will confirm im right, anyone with a brain will confirm im right. There would only be 2 options left. 2 options cant make a 2/3 chance.

Nathaniel Nelson
Nathaniel Nelson

Once a gold is drawn, only 3 options are left, a silver, gold #2 from box 1, or gold #1 from box 1, so its a 2/3 chance.
FTFY

Adam Gonzalez
Adam Gonzalez

50/50, it states that one box contains no golden balls.

Carter Price
Carter Price

1/3 so 33%. Whoever said 50 is a fucktard.

Brayden Cruz
Brayden Cruz

The probability of whatever happens is 1, otherwise it wouldnt' happen

Owen Lopez
Owen Lopez

explain your reasoning process

Bentley Perry
Bentley Perry

I can almost grasp this but at the same time, not.
Ifni draw gold all I know for sure is I didn't pick the all-silver box. The the question is what are the chances of picked one of two possible boxes. That's gotta be 50%.
Like after I already drew gold, the remaining question doesn't care what the probability was that i drew the first one--whether I took it from a box of all gold or not.
All that remains at the core is, there's three boxes: you've confirmed that you didn't pick box 3. What is the remaining probablility you picked box 1 rather than box 2... And that is a coin toss, aka 50/50

Bentley Long
Bentley Long

Holy braincell. This is the most retarded shit I have ever read

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Aaron Clark
Aaron Clark

It's 2/3 you retards.
If you got a gold ball it's more likely you got it from the two gold ball box than the one gold ball box.

Isaac Cook
Isaac Cook

Just shake the box to make sure you know beforehand

Easton Wilson
Easton Wilson

Im And like I said, after you already drew the gold ball it doesn't matter which box from which you were more likely to do so. It happened,and it rules out one of the three boxes. That probability doesn't affect the coin toss of which of the two gold-containing boxes you drew from

Gavin Scott
Gavin Scott

I just typed this up, you can try it yourself if you have an IDE.
Imagine the situation is similar but in each box are 10 balls instead of 3, in one box you have 10 gold balls, in another you have 10 gray balls, and in the third you have 1 gold ball and 9 grey balls.
If you have gotten a gold ball by random chance, which box do you think it comes from?
Look up the goat problem.

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Hunter Turner
Hunter Turner

*monty hall problem, not goat problem.

Brody Butler
Brody Butler

Clear bait IMO

Colton Brooks
Colton Brooks

I did it in matlab.

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Austin Foster
Austin Foster

Can you explain why it's not 50%?
Since there's a gold ball, it has to be either first or second box, there are only 2 outcomes either i pick up gold ball again or a silver one since box third is out of the question by logic.

Ian Price
Ian Price

6 possibilities

Picked the box with two gold balls, picked its first ball
Picked the box with two gold balls, picked its second ball
Picked the box with a gold and silver ball, picked its first ball (gold)
Picked the box with a gold and silver ball, picked its second ball (silver)
Picked the box with two silver balls, picked its first ball
Picked the box with two silver balls, picked its second ball

It's not the latter three as they all involve picking a silver ball first. Of the three remaining possibilities, two lead to picking a gold ball the second time around. The probability is two in three.

Jaxon Howard
Jaxon Howard

This is a good explanation.

there are only 2 outcomes either i pick up gold ball again or a silver one
Just because there are two outcomes doesn't mean the chance of each outcome is 50%. When you buy a lottery ticket, you either win, or you don't win, but that doesn't mean you have a 50% chance of winning.

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Jace Adams
Jace Adams

There being two outcomes doesn't mean that each is equally probable.
All you know is that you got a gold ball, you don't know which box you got it from.
It's more likely that you got the gold ball in your hand from the box with two gold balls (two times more likely, to be exact)
Since the question says GIVEN you drew a gold ball you work backwards to determine which box it likely comes from.
I think most people when they answer 50% have this mindset:
choose random box, which box did you most likely pick if it was one of the gold boxes?
When they should have this mindset:
given that you drew a gold ball, which box is it more likely to have come from?

Joshua Flores
Joshua Flores

Imagine responding to a bait
Imagine responding to a bait seriously
Imagine that "running a simulation" on a 3rd grader math problem will stop the trolls

Just sage

Landon Butler
Landon Butler

it can be one of two things
thus the probability of those two things are an even split
yikes

Hunter James
Hunter James

I'm gonna reply to your post so your sage was useless :)