I DIDN'T GET THE FUCKING JOB BECAUSE I DON'T KNOW WHAT MODULO IS

or... you do not even need to know modulo.
(x&1) == 0)

Well he should know it lmao if hes gonna go apply for a serious job anywhere

>perse as a pronoun

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>C doesn't have a guaranteed order of evaluation
wrong
in general it does not, but it specifically does have guaranteed order for &&, ||, ?, and , (comma)

It may be slow but it is never going to slow your code down in any meaningful level in a practical application.

If your code will ever be read by another human, don't obfuscate your code with custom functions that get barely any noticeable gain, dumbass.

Lol needing doubles for this logic

Deserved.
Every programmer should know what modulo is. literally Programming 101

Even if you didn't know modulo somehow (I would never hire someone who doesn't know such a fucking basic operation), you can very easily make an O(1) modulo function. Checking if even is by far even simpler.

You could have done ((n&1)==0), (((n/2)*2)==n), (((n)

Man, I feel dumb. I did this nonsense,
x / 2 == x >> 1

but your answer makes so much more sense.

>Didn't know what modulo is.
I wouldn't hire you either, you'll find a retarded and inefficient way to do everything because you don't know the basics.

>what is the problem?
they didn't want you

>function is called isEven, returns void
>function takes no parameter to check if its even
>double x
>for loop to 100
>divide by 2
>useless cast
>std::cout

This is a carefully crafted bait I guess

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Don't forget double i

It needs to be double, C is outputting in half of a loop.

what is the the point of assigning x in the if statement instead of in the line before it?

you didnt know what's a modulo
i remember learning abt that in 7th grade lel

the program never halts mate so no it doesnt even work dingus

No, it's constant time. For all intents and purposes, just as fast as any other operation.

Should have just done a bitwise check of the last bit in variable i.

Not if it is modulo 2 as in the OP. Compiler optimizations, newfriend

>(x = i/2)
Returns 0 (false) for i==0, right? So your solution does not work. If I saw this code I wouldn't have given you the job either

>posts a statement without proof

Get % retards lol

>No, it's constant time.
wrong

Is this bait?

>Returns 0 (false) for i==0, right?
This is true.
Learning modulo is one of the basic parts of learning mathematical notations in programming. I imagine that a large number of people skip it because they think "what do I need math for" but basic mathematical equations are so important for any programming that if you don't know how to do them in the language of your choice you're basically worthless.

>The absolute S T A T E of webdevs
>C++ answer
>Assumes webdev

In most cases this is already implemented in the compiler. In C# you can also use pointer but it's usually slower because the compiler doesn't optimize as much as without.

It is correct. For any given data type on the left side of the operator, there is an upper limit on how long modulo can take to finish, which is referred to as "constant time" in complexity theory. And there are only finitely many basic data types which can be used on the left hand side of the modulo operator

Okay prove me wrong you retards.

Here's a solution that actually works and doens't break.

Attached: Untitled.png (726x397, 23K)

Reinventing the wheel with unreadable code.

Here's what I'd do:
bool isEven(int n) {
return (1 & n) == 0;
}

You should have made it interactive, ie:

>0 is even, is this the even number you were looking for? [y/n]
$ n
>2 is also even, is this the even number you were looking for? [y/n]
$ n
>4 is also even, is this the even number you were looking for? [y/n]
$ n
>6 is also even, is this the even number you were looking for? [y/n]
$ y

kek

most people on Jow Forums don't know how to code and you replied to a retarded tech illiterate (he
s probably a zoomer too)

DAMM Javscript looks like THAT?

>I DIDN'T GET THE FUCKING JOB BECAUSE I DON'T KNOW WHAT MODULO IS
How do you not know what modulo is when applying for a programming position? It’s like not knowing how to write an inline conditional statement.

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>double

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Literally high school math.

Is this actually a thing? I work with a lot of people who could be considered webdevs and I'm almost a 100% sure all of them know what a modulo is.

void isEven() {
for (int i = 0; i < 100; i += 2) {
std::cout

Hahahaha you dumb fucking frog!

>I DIDN'T GET THE FUCKING JOB BECAUSE I DON'T KNOW WHAT MODULO IS
Good.

>not knowing how to write an inline conditional statement.
Is that like x = i < 2 ? ifTrue : ifFalse

T. Zoomer learning c++