Does anyone else suck at these goddamned numerical tests or am i the only brainlet here?

Sure dude, cope in whichever way you want

above solution is too complicated.

it's literally a unit conversion problem.

left chart is g/km, right chart is km/litre. you need to solve for g/litre. it's straight multiplication accross and taking an average.

((120*17.2)+(145*17.2)) /2 = 2279

dude, a 13 kid cal literally solve this w/o calculator.

wtf how u are retarded

>carbon dioxide is bad

>excess CO in the atmosphere isn't a bad thing.
Wow, this way of arguing is retarded, never tried it before.

*CO2

those numbers are made to be nonsensical, as climate change is a hoax

0.5*17.2*(145 + 120)

The main issue that would prevent me from answering this question is that it makes no logical sense. You get different fuel efficiency highway vs city driving. This question wants you to assume you get the same efficiency but magically different co2 emissions. Plus it says you emit more co2 with highway driving which is the opposite of how it is in real life. It breaks my brain and I couldn't begin to answer the question.

and they drove till the tank was totally empty.

to calculate a average you literally just go (a + b) / n = average

n = total of numbers you're calculating the average for

>food analogy incoming
so let's say you eat 1 apple and older brother eats 3 apples, while your younger brother ate 2 and somebody asks your father how many apples his sons have eaten on average:

(1 + 2 + 3) / 3 = 2 apples average

this is fucking high-school freshman-tier in europe, I'm not even trying to shittalk you americans, I genuinely feel sorry for how your education system is failing you like it did this guy

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What the fuck are you on about? What's the answer then?

this feeling

first you check how far the car goes on a full tank

energy efficiency: 17.2 * 30 = the car can go 516 km on a full tank

then you divide that by 2 and calculate both of these with the highway / city values since they're defined as exact halves, so you get the total CO2 in grams

145g * 258 = 37410g / 258km aka CO2 total on highway half
120g * 258 = 30960g / 258km CO2 total in city half

then you divide both totals by 15, which is half of the fuel tank and that gives us the value of g per liter

37410/15 = 2494g/l on highway
30960/15= 2064g/l in the city

then you calculate the average between these two and bingo:

(2494 + 2064) / 2 = 2279 g/l on average

this guy was right by the way, you people misread the question as "average by kilometres, rather than average by litres and I take back what I said here and all of that is the complicated version, the easy version would be where you directly calculate the g/kg to g/l (1 l being equal to 17.2km which means we can just multiply bith with that), and then calculate the average and bingo again:

[(145*17.2) + (120*17.2)] / 2 = 2279 g/l

if you guys need to git gud at maths etc. I think you might want to head over to khanacademy

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