What's the answer, Jow Forums?

Lol

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Then it's 50%
hodling BTC

chainlink

wait nevermind i change my answer to 1/3

and i am all in on BSV

50/50 you can rule out the double silver box as soon as you pull a gold. So your hand is either in double gold or the split one

BTC

2/5 probability

2/3 largest holdings right now are AAL and silver

I know the trippy BS people try to say to explain how it's not half but it honestly is half, giant paragraphs to explain how yellow is technically green don't matter in practical life.

33%

You have 3 boxes.
What are the odds of picking the box with 2 gold balls? 33%

holdings?

Jesus the cope. Imagine believing statistics doesn't matter in real life.

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Holdings sir?

>cant into probability

2/3

1. The initial chance of picking Gold is: 3 Gold/6 Balls Total, 50%.

2. After picking a Gold ball, you can remove the 2 Silver Balls in one box from consideration. This reduces Total Balls to 4.

3. Of these 4 remaining Balls, one has been found to be Gold. This reduces Total Balls to 3 AND reduces the amount of Gold Balls to 2.

Therefore, the likelihood of picking another Gold Ball is 2 Gold/3 Balls Total, or 2/3.

Highest holdings are XRP, Link, BSV

2/3

yeah i just checked the answer and it doesnt make sense

math will never have any bearing on real life like that. if you think about it numbers dont even exist.

Its 50%

BRAP

100% in Chainlink here. I knew the answer was 50% in under 5 seconds. Surely these gentlemen are trolling.

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cope

66% chance next ball is golden
Lit

You can just admit you are a brainlet fren. Nobody is gonna judge you.

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2/3, eth

You cant see inside the boxes
this guy is right

Eliminate the silver box , obviously 2 of the 3 is the box the one gold came from, its down to 2 boxes, it is a 50% chance at that point you pull the next one out of the SAME box.

but you are guaranteed to get either the first or second box, so the third is irrelevant. The question is flawed because its impossible to guarantee something if you are picking at random.

The point of the thread is to also post your biggest holding along with your answer you niggers.

Id rather shitpost

It's 50% fucking brainlets kek
Link $1000 EOY check em

Mostly ETH
Oh, and Pi Network (Soon to become the majority of my equity once it goes public)

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you are the first to post your holdings but not the answer lol

Oh sorry,
>pic related

inaccurate representation of the probability space. drawing a picture may help but you should really draw all the possibilities before you start eliminating.

so your answer is 50%?

Yeah

I know, the real answer isn't 50% to those who truly know what's up.

Bertrand's box paradox is boring and you aren't smart.

NEXT

LINK
3/5

I'm strong enough to just take all the boxes.

My biggest bag is Ethereum.

2/3, LINK
This is a meme. I believe that half of the people who still say 1/2 are trolls that want to feed brainlets.

It’s impossible to pick a gold ball from the one with 2 silver, so you eliminate that one in the calculation. So if you have removed 1 gold ball you are either working in the 2 gold ball container or the 1 silver and 1 gold container. With 1 gold ball removed in the one gold one silver, there can only be one silver left , and in the 2 gold ball container there is only 1 gold ball left. So therefore it’s 1/2.

2/3

The problem is equivalent to asking “what is the probability you have chosen box #1?”

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think of it this way, you are effectively sampling evenly from the space of six balls.

conditioning on having taken a gold ball first, 2/3s of the time you would have done this by selecting the two-gold box.

the answer is irrefutably 2/3.

LINK + XTZ gigachad master race.

You are twice as likely to pick the box with two golds in it when you pick a gold.

To me, 25% actually makes the most "sense". 3/6 * 1/2. As soon as it asks you to choose another ball from the same box, the outcome is either Gold or Silver.

I guess the issue with that thinking though is it's not just 1/2 initially. You can choose from 3 boxes, each containing 2 Balls, you're not limited to choosing from a single box which would reduce the Total Balls to choose from to 2.

Because of that, you need to be able to account for not choosing from a box which contains only Silver Balls.

But pulling out a gold ball proves that you didn't get a silver box. The odds are now 50/50. The silver box is dead and gone from probability.

Is this a testical joke?

What?? How are you more likely to pick a gold than a silver? It’s 50/50 mongroid

Given that you have chosen a golden ball on your first go, it is more likely that you have box 1. 2/3 of the times it will be box 1.

That's means you have a 2/3 chance of your next ball being golden, and 1/3 chance of it being silver.

50% with full certainty

All in Elastos

2/3

Read the question

Google the problem retard

brainlets

This is the best layman's explanation that anyone can hear, it's up to them to understand it.
All these brainlets just got dabbed on by a reddit spacer.

This is correct. 50/50 irrefutably

50% I think
it's either box 1 or two that means either the other ball is 100% dud or 100% gold

It’s 50/50. Anyone who says otherwise is retarded. I have googled the problem. If you simulated this problem a million times and only counted when you drew a gold ball on the first grab you would end up with 50%

Show us your code.

I thought it was 50% too until I read the solution and then it made sense. Anyone calling people brainlets for answering 50% are even bigger brainlets because they weren't able to explain why it's not.

So, the first ball is gold. That means there's only 2 boxes it could be. GG or GS. The fact that it's two boxes doesn't actually matter and this is why so many people think it's 50%. There ISN'T 4 balls left, there's 3. The 3 balls are GGS. That's why your chance of picking another gold is 2/3 or 66% and not 50%.

So yeah, I hope that clears up some confusion. I originally thought it was 50% too.

Please, do run the code. Just as with the Monty hall problem, you will see that statistics prevails over your pebble brain logic.

Imagine it this way. You pick one of the three boxes, you draw a gold ball, what box is it most likely that you have drawn from?

Dab

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there's 3 unchosen balls, but the next ball has to be either a gold or a silver (2)

>You pick one of the three boxes, you draw a gold ball, what box is it most likely that you have drawn from?

This is a brainlet explanation and doesn't even make sense. You aren't more likely to have chosen GG because you picked one gold. Whether you have GG or GS is 50% if the first ball is gold.

Combine the 2 boxes with at least 1 gold ball.
GGGS. Remove 1 gold. GGS. How is that 2? It's not. It's 3.

66%
LINK

Lol these threads always deliver. Would expect biz of all the boards would have a basic grasp of stats. Anyone who didn't answer 2/3, you have shamed us. Remediate.

BTC

Here is the solution.

This probability is
2/3
. Let's do an informal computation. It will be imprecise, but could be made precise by using the notion of conditional probability.

Imagine repeating the experiment 3000
times. Then each box will be picked roughly 1000 times. We will get a gold coin about 1500 times. Out of these 1500 times that we get a gold, it will have come from the two-gold box 1000 times.

So if we restrict attention to the 1500 times that we get a gold, about 1000
of these times it will come from the two-gold box. So given that we got a gold coin, the probability the other coin in the same box is gold should be around 1000/1500
You come in with a problem you copy and pasted of google and pretend to be smart but can’t explain the solution
.

If anyone wants the solution written by someone who isn't a pseud, it's here: A person who truly understands something can explain it simply, as I have. The dumbest person is the one who can't explain it at all, which is most of this thread and most of Jow Forums.

Chainlink is a scam, by the way.

You got the solution wrong dipshit

>literally just replied to say "ur wrong"

Thank you for proving how dumb you are.

Some made retarded people here
3 boxes. You draw a gold bal, that eliminates the SS box (#3) you picked from either the GG or GS box. Since you took a gold ball, in those boxes remain either a G ball (#1) or S ball (#2)
Thus 50-50 thus 50%
If you dont get this highschoolmath you are beyond hope and you should seriously question yourself

Your solution assumes you are drawing from either box. You are drawing again from the same box. Now fuck off.

No, your explanation is terrible. It's not a proper solution.

Let me break it down like this for you. You choose a box randomly, 1/3 it is box 1, 1/3 of the time it is box 2, 1/3 of the time it's box 3.

That means 1/3 you are guaranteed to have no chance of having drawn a gold ball (box 3). 1/3 of the time you are guaranteed to have drawn a gold ball (box 1). 1/3 of the time you have a 50/50 chance of drawing a gold ball (box 2).

2/6 of the time you will draw a gold ball from box 1.
1/6 of the time you will draw a gold ball from box 2.
1/6 of the time you will draw a silver ball from box 2.
2/6 of the time you will draw a silver ball from box 3.

So there are 6 possible outcomes, and 3 result in a gold ball. Of those 3, 2 occur when you select box 1. That means given that a gold ball has been drawn, you have a 2/3 chance of having selected box 1.

PICKS FROM THE SAME BOX YOU ABSOLUTE MONG
FUCKING READ

Wtf another mad retard

You're misquoting Feynman, a person who truly understands can explain it simply to an audience of undergraduate students. When a reporter asked Feynman what he got his Nobel prize for he responded that if he could explain it to normal people he wouldn't have gotten the prize.

>The fact that it's two boxes doesn't actually matter and this is why so many people think it's 50%.
im a brainlet so why does the box not matter
The box in front of you, that you have ruled out not being the SS box, does not contain 3 balls. It contains 1 ball. That one single ball is either G or S.

>You choose a box randomly, 1/3 it is box 1, 1/3 of the time it is box 2, 1/3 of the time it's box 3.

I stopped reading here because you're already wrong. Theres a 0% chance of it being both silver because we KNOW that the first ball is gold.

>You are drawing again from the same box.
Yes. We know it is the same box but we don't know whether our box is GG or GS meaning we could be drawing from either.

This is my last post in the thread because the people here are just too stupid to even reply to. Which is why I do very little conversing on Jow Forums and spend most of my time scrolling past or filtering threads.

100% bitch

It’s 2/3 bitch. What’s your major holding so I can short it

2/3
Took me 10 seconds to get it and doublecheck.

Fuck off absolute retard.
I try one more time: either box GG OR GS. Drawn G so either an G or S remain
YOU DRAW FROM THE SAME BOX YOU HIGHSCHOOL FAILURE.
You either draw the second gold of the GG box or the silver one from the GS box
59% mongoloid

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>calls other people highschool failures

1/3. The only box that can fulfill that request is the box with 2 gold balls. The chance of you picking that box is 1/3.

Also, Sent and Ren.

You already drew the first golds you retard. This only makes sense if you put the gold ball back in there after drawing the first time

Whoops. Reread question. The answer is 1/2 .

If you cant do this, you botched highschool, fact
These are the people im trading against kek

You started with a gold ball. There are three gold balls. Therefore there is a 2/3 chance you picked from GG box, 1/3 chance you picked from GS.

Probability is my favorite branch od mathematics.

Nigger what. How do I help these people?

What's your biggest holding?

gotcha. thanks user.