Library closes in 5 hours

>library closes in 5 hours
>have to learn the area between a curve and the x-axis by tomorrow

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Just divide the curve arc's area squared by the hypotenuse of the right triangle laid against the x axis you stupid fuck...

>doesn’t know how to do an integral
>is over 18
>thinks he’s gonna make it

What this guy said u stupid fuck

If you know how to differentiate you already know how to integrate if you are not a brainlet.

w-why are you guys so smart? I thought we were only neets and brainlets who shill our shitcoins to each other

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Do the definite integral. I forgot most of this stuff but it's easy to find on youtube. Search there instead of browsing Jow Forums

When i was in school there was no youtube. Now there are shitloads of videos to teach you. Even tho the ADL will prevent any criticism of jews

Wrong. It was only you all along

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im fucked

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Im already such a boomer (25) that im already starting to forget high school stuff like that..

Just set the two formulas equal to each other and find the quadratics, numbskull

I saw a similiar thread yesterday and the have also spoonfed you OP
should we also teach how to buy link?

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Take the goddamn definite integral. This is how you do it: integrate the given function P= (5-Q)/2, and then apply Barrow's law to the result, which is: the difference between the integrated function evaluated in 3 and and the integrated function evaluated in 0. This should be a concrete single number, which is the area.

Also look this vid if you can:

youtube.com/watch?v=FnJqaIESC2s

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/sci

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This is actually ultra easy.
Things will get quite a lot harder if you study economics

Yes. OP will have to work his ass out of this. I'm just about to have an exam on my last subject on mathematics, doing an econ. degree. I seriously recommend these textbooks: Calculus by Thomas, Essential Mathematics for economics by Sydsaeter, and Mathematical tools for economics by Alpha Chiang. Otherwise he'll get BTFO

How many times are you gonna post your homework here?

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If you're not smart enough to learn how to do it at least be smart enough to Google "how to define an integral on a TI-83 calculator".

t. Braindead wagie with engineering paper

I haven't touched calculus in 7 years but...

1. anti derivative of 5-2/Q is 5Q/2 - Q^2/4
2. evaluate the above at Q=3, and Q=0
3. the difference between these two values is your answer

y = -.5x + 5 is the equation for the line I hope you learned in high school. The 5 comes from when x=0, and the .5 is y/x intercepts so 5/10. The - is because of a negative slope.

So you now do the integral to find the area.
It's hard type out but hope you can follow.
I haven't done calc in 7 years but I'm pretty sure this is right:

y= -(1/2)x + 5
Y = -(1/4)x^2 + 5x
Y(3) = -(1/4)(9) + 5(3) = 12.75
Y(0) = 0
Y(3) - Y(0) = 12.75 that's your area

my bad I'm a dumbass I don't know how to read fractions anymore. anti derivative is 5Q - (Q^2)/4. So the answer is 5(3) - (3^2)/4 = 15 - 9/4 = 12.75

if you dont know how to do that and youre in a non meme engineering course i would recommend you to drop out asap. it gets much harder.
its even a straight line so you can easily cheat and not use integral at all, Q=3 then P=3.5
3.5*3=10.5
(5-3.5)*3/2=2.25
10.5+2.25=12.75

You idiot

It doesn't look like an engineering course, probably intro to calc for business/econ.
OP is one of the meme students who can't even google solutions