Jow Forums Apps

What iPhone and Android apps do you wish existed but don't because of (((political taboos)))? What about simply useful apps for Jow Forumslocks? Equity in a startup I worked for a few years ago paid off this year so I'm independently wealthy and have nothing better to do, and I was thinking about making some Jow Forums apps, or just useful apps in general.

Looking for some serious suggestions
>pic unrelated but I saw it posted here over Christmas

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Other urls found in this thread:

en.wikipedia.org/wiki/Bertrand's_box_paradox
en.m.wikipedia.org/wiki/Bertrand's_box_paradox
twitter.com/SFWRedditVideos

yall want some apps?

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50%

>German intellect

GPS that avoids black neighborhoods.

He’s right. There’s only two possible outcomes. The second ball is either the other gold ball from box 1 or the silver ball from box 2. 50% chance of getting a gold ball.

>There’s only two possible outcomes
>that makes it 50%
lol...

One box is 100% silver

One box is 100% gold

50%

Easy

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2/3.

pretty solid idea, but I think recreating an actual decent navigation app which is actually comparable to the existing options probably isn't worth it just to add that singular feature

Don't post a picture more interesting than the question

If you have one gold ball in your hand, it means that you're more likely to have picked the GG box.

So you have to weight the probabilities, not just assume it's 50 / 50.

The answer is 2/3.

50% obv

The idea is that the result is skewed by meta-chances. The chance that you would grab a gold ball to start changes the following ball, because one box has two, therefor it is most likely you grabbed the box with two gold balls in it.

tfw I drove to see some relatives on Christmas but I didn't get into a car crash

thank fuck, that 50% chance of crashing is really scary!

FFS bruder, 2/3 is correct.

>using racist math to oppress your fellow countrymen

That’s not even a remotely comparable situation.

Fair enough, I didn’t consider that.

>That’s not even a remotely comparable situation.
>there are two outcomes therefore it must be 50% hurr durr

I am not even your brother
I am slavic but i live in germany

>false flagging slavs

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50/50

two yellows are cancelled out by the two grays leaving a 50/50 chance of picking yellow or gray.

Now dis nigga is thinkin'.

The pic is only asking about the probability of the next pick. You already have a gold ball and there are only 2 choices.

>and there are only 2 choices.
there you go again

Oversimplifying the problem leads to getting the wrong answer. It's 66%. For the app question, probably dating apps that let you select more filtering criteria like race, no kids, employment.

Just imagine if it was real life bro.

Once you got that first gold in your hand it means you're more likely to have picked the GG box.

Wrong

When you pick from 2 boxes there is a 3/4 chance of pickung a gold ball

Given that you already picked the gold ball you are now faced with 1 box being potentially 1 of two previous boxes

1 previous box is 100% gold

1 previous box is 100% silver

1+1=2

You are picking 1 of those 2 boxes

1/2 potential boxes have a 100% chance of being gold therefore your box has a 50% chance of producing a gold ball on a second drawing

Either the GG box was ignored in the first pick or the GS box was ignored on the first pick

They cannot have both been picked.

No wonder the jews tricked king arther with Merlin the pedowizard, no wonder you sold out to banks first and no wonder we beat you with pitchforks.

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>For the app question, probably dating apps that let you select more filtering criteria like race, no kids, employment
Interesting idea, although there are already alternative dating apps, like Christians Mingle and such

Correct

66.66666666666666666666%

Why people keep taking this slide bait? Sage

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I can't decipher your illiterate ramblings.

There are 3 balls left in the scenario presented u nig. 2 of 3 are gold.

based

>2 boxes left
ROUND 1: 100% gold GG vs 50% gold GS
>G confirmed
>1 box left either _G or _S
ROUND 2: 50% chance G, 50% chance S

I hope 1 person is not trolling but it's fun anyway

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You're thick as shit bro.

Fucking lowlife jabroni. Imagine being this bad at mathematics. What a fucking joke.

3 balls dont matter when 2 are in a box removed from the choice

There's 1 ball and 1 box left and all you have are the chances of it being a color

What's the matter gayboy? Big boy maths too dificil para ti?

Ad hominem no argument for a math problem

Checkm80

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It's goyboy to you jew

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No, but it's an argument for you being a fucking retard.

either picking from the box that has another guaranteed gold (100%), or the gold/silver box(50%)

75% the ball is gold

Irrelevent when we are talking math

Retard.

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The probability is 1 if the box was GG, else it is Zero, if box was GS. There are 2 boxes with G, and there are a total of 4 balls, 3 are G.

Having selected 1 G, AGGREGATE probability of getting another G is 2/3.

How do you not get this

God you're stupid. What on earth is wrong with you? Where'd you study mathematics? Dumb fuck jabroni.

You cant switch boxes

You have 1 of 2 potential boxes you are picking from and you don't know which it is either it's got 1 silver ball or 1 gold ball left and you only have 1 ball to pick.

2/3

>being a faggot phoneslave that cares about apps

No, fuck yourself, I like my Nokia from 2006

If the box was not removed after the choice, there could be more possibilities

When you are forced to pick from the same box, there's only 1 ball left and it's either the leftover gold or the non-gold

No argument

Kill yourself soon

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come back 2 portugal

This is just a restated version of Monty hall.

Let me restate the question. You put your hand in the box and pick a gold ball. You can turn the gold ball in for half it's value and walk away, or pick the second ball, and if the second one is gold you get double the reward.

What do you do. Of course you pick another ball. 2/3 chance it's gold.

RETARDS

>You have 1 of 2 potential boxes you are picking from and you don't know which it is either

It's more likely to be the GG box (because you already have 1 G in your hand). So you have to weight the probabilities.

P.S. You are as thick as shit and a disgrace to your family. Have a good day and go fuck yourself.

Feliz Navidad hombre.

Your original choice affects your second choice. You wrong, nig.

The prob of picking box with G is not relevant. Having picked a box with G, the prob of picking another G is 2/3

There are 4 balls, G1, G2, G3 AND S1. prob of picking any of the G is 3/4 round 1. Having picked a G, prob pick another G is 2/3

No wonder you got the wrong answer

I know you're only pretending to be retarded, but in my undergraduate stats program there were plenty of people who didn't understand that you can't retroactively apply transitive properties.

Probability was removed when it was stated that you already drew a gold. The boxes have been narrowed to two choices 1 has another gold, the other has a silver all previously needed chance/probablity has been removed by the question's stated situation. 50% chance its gold

You don't pick balls, you pick boxes THEN balls. Moreover, in the first box, there is no gold-gold. There is just gold. It's a singular chance of having picked gold. You could've picked the gold from 2 boxes. 100% chance for another gold from box 1. 0 % chance for another gold from box 2.

50%

>Given: First pick G
There was a 1/3 chance you chose the box with only a silver ball left and a 2/3 you chose the box with only a gold ball left.

Simplify your explanations.

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See

Only the probability of the second pick was asked. You would be right if it asked 'what is the probability of drawing Gold twice if you have a guaranteed Gold on the first try'

Wrong. There is 1/2 chance you picked the gold-silver box. There is zero chance you picked the silver-silver box. Why? Because the ball is already picked, remember?

You have to draw from the SAME box again. You've already got a gold ball so you've picked EITHER the GG or GS box. It's now a 50/50 chance which box you have. If you have the GS box - remaining ball is silver. If you have the GG box - remaining ball is gold.

This.

Pure math states 2/3.
Reality states 1/2.

Hence why it is called a paradox.

2/3

No, Suomi, you're not understanding him. He means that before the choice there was a 1/3 chance of picking the double silver box, and a 2/3 chance of picking a box with a gold ball. You're on the same page.

1/2
THERE ARE TWO REMAINING OPTIONS. ANYONE THAT SAYS OTHERWISE IS A SHILL.

You dumb fucks should all go out buying lottery tickets considering you have a 50% chance of winning.

This is literally your line of reasoning.

Ah okay, thanks.

Pure math is wrong. The story problem is actually: You have a box that 50% of the time has 2 gold balls.

It literally isn't.

The whole point of this shit is to prove pure logic and math gets fucked when meeting reality sometimes.

See
Simplify your explanations.

Don't waste ammo.

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I'd buy a ticket desu

If you distinguish the balls in the first box, you will get a probability of 2/3. If you don't distinguish them, you will get 1/2. So take your pick.

en.wikipedia.org/wiki/Bertrand's_box_paradox

There you go retards. Have fun being retarded.

EAT SHIT STUPID FAGS

en.m.wikipedia.org/wiki/Bertrand's_box_paradox

2/3

Thanks bro. Nice digits. Have a splendid evening

>Given: 1 of 3 gold balls picked, 1 silver ball not picked
2/3 chance it came from the box with only gold left, 1/3 chance it came from the box with only silver left.

Bonus: You can't change boxes and the silver only box is just for show because it's removed from the equation given that you were told you didn't pick it.

Not the same problem.

Canada and UK showing how it's done.

Happy Christmas and Joyeux Noel my Canadian hombre.

I'm aware math is wrong. That's the whole point of this paradox.

People seem to think that pure math can't be wrong. It can be.

It's like Schrodinger's Cat. Idiots claim it shows how things can exist in two states. The whole point was that the cat is either dead or alive not in between.

Yup, proves my fucking point.

The pure math isn't wrong, retard. If you carried out this experiment in real life the results would still be 2/3. Dumb fuck.

Literally, go and carry out this experiment now. The results will tend to 2/3.

But simplifying the answer in your own words was the purpose if the exercise on Jow Forums

Clearly you were not coming to Jow Forums just to argue about basic probability problems were you?

A 50/50 chance. Any different, and you"re a retard!

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You mean one of those "problems" that math nerds use as party tricks because they like to abuse numbers to make seemingly impossible results?

It can't possibly be 66% to get two gold balls because 66% of the time you picked the wrong box. So the only correct answer is 50% because the story problem really is stating you have two boxes, one that is right, one that is wrong, what are the odds of picking the right box.

So anyone saying it's a probably of 2/3 is just lying. I don't care if some formula says it can be that way, in reality IT IS NOT.

But thenpoint of posting these on Jow Forums is to argue and find out who can win

You must provide the answer that can be understood

"There is a 2/3 the box you have is the one that only has a gold ball left and a 1/3 chance the box you have is the one that only has a silver ball left. Questions?"

The exercise was not to be a fucking ignoramus.

Some of us passed, some didn't.

That's fucking impossible you god damn moron. It's always going to be picking the right box 33% of the time. Unless you're going to discard every person who picked the silver ball as their first ball. But thanks for showing how statistics can be fucking abused.

We arent talking about picking 2 gold balls

Were talking about picking 1 ball from an uncertain box that has probabilities concerning what color the ball inside is.

I havent played one of these stupid Jow Forums math arguments in a long time

I felt like playing when offered a challenge

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This problem can't be carried out in real life, since the problem begins at a point where you have already picked a gold ball. It begins at the round 2. In an experiment you would have to manually perform round 1. This would create the 2/3 answer, which would be wrong because the problem would no longer be the same it was in the OP.

Except we know which boxes have what. So if you pick a gold ball, the silver box is discarded as if it were never there. Then there's just two possible boxes, one that has two gold balls, one that has one. It's all about the gold balls.

Yes, part of the experiment would be discarding the cases where the silver ball is picked first.

Because that's part of the fucking question.

You truly are a fucking moron.

Run the experiment yourself, fucktard. Just don't forget to use all three boxes when you do.

See
Congrats on being another fucking retard.

When you pick a box you have a 50% chance.

After drawing the first ball we now have more information, because you're more likely to draw a gold on the first draw from the box that has nothing but gold balls in it, so we can update our guess (probability) to be 2/3rds because of the new information.

Now you know.