BRAINLET TEST

i call 10 cm

Obviously 12cm you fucking retards.

8 cm

do you know what a base is?

if an 11 year old can solve that pic then yes, they're smarter than me.

No, but I know all of them are belong to them.

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12 cm

where's my prize?

The whole thing is 1600 cm, and it's split equally into 4 triangles.
A of triangle = 1/2b*h
400 cm = 1/2b * 80cm
b = 10 cm

For all the dumb cunts that cant solve this:

Total area is 1600. The sheet is divided into 4 equal triangles, meaning 1600/4 = 400, which corresponds to the area occupied by each triangle.

The area of a triangle is given by the following formula: A= b x h/2

Replace with the number given and the area you just discovered and you have the measurement of the base, which is 10.

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I got 10cm
>Divide the total area by 4 (because there are 4 triangles where there height is known)
>knowing the formula to find the area of a triangle is A=(bh/2), solve 400=80b
>each base is 2 triangles bases
>voila

how the fuck are you supposed to know this shit? Fuck math. I'll just be a stripper.

It might be 20cm, I dont know what a fucking pennant is

Now that the first one has been explained to you, solve this.

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44.5 square feet

fuck puzzles

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44.5 ft.
Area of blue rectangle = 6 ft. * 4ft. = 24ft.
Area of pink rectangle = 5 ft. * 5.7 ft. = 28.5 ft.
Area of right triangle = 1/2 * (4 ft. * 4 ft.) = 8 ft.
Total area = Area of blue rectangle + Area of pink rectangle - Area of right triangle = 24 ft. + 28.5 ft. - 8 ft. = 44.5 ft.

>fuck puzzIes

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area is 1600cm2
width of the parallelogram is 80cm, so length is 1600/80=20cm
the parallelogram's length consists of two pennant bases, so each pennant's base is 10cm

For the lurkers who keep failing, know this: if you cannot solve pic related, you will be working in a grocery store at 40 years old.

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This problem is poorly constructed. Because 2(4^2) isn't exactly equal to 5.7^2 if the student works with the 5.7 ft they'll get a different answer. Sloppy work on the test maker's part.They should have made the pink rectangle's corner on the bottom extend slightly rightwardly past the teal rectangle in the diagram, and possibly made the pink one an even 5x6.

area of square is 9x9=81
area of each triangle is 3x3/2=4.5
4 triangles 4.5x4=18
81-18
=63 square feet

63 ft^2
units mah boi
FAILED

I just found the unknown side of the parrallelogram and then halved it to get ten. The weird thing is that there's no way of telling if the pennants are really all the same size and whether the 80cm line is orthogonal to the shorter side. There's no angle information to tell

Another way to solve this is to know that the area of a quadrilateral is its base times its height. We can solve for height by dividing its area by its base.

1600/80=20cm

We can also see that the base of the pennant is half the height of the entire shape, so we divide the height by 2 to get our final answer.

20/2=10cm

I agree with OP, if you can't figure this shit out then 11 year olds are smarter than you.

It implies the bases are equal in length. It's somewhat safe to assume the top and bottom lines are parallel but a couple marks could make that more clear, eliminating all confusion.

>test3
9

Ready for another type of problem, kids?!

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GCF is 18

why the fuck can't these be multiple choice?

8 boys per row

10 girls per row

9 rows per gender

18
18x4 and 18x5 respectively
The fact that one is 18 lower than the other makes that too easy.

18, its the GCD of 72 and 90

Because 11 year olds solve this, buddy.

Now make me an Oreo McFlurry, thanks.

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what is a pennant?

>Because 11 year olds solve this, buddy.
yeah at some prodigy school maybe

3 pencils, 1 calculator

>10 cm
There are 4 total triangles in the figure
>base x height/2 is the area of a triangle
1600/4 is 400 if we assume every pennant is identical.
Each triangle has to be 400 cm^2.
Since b x h/2 is the area, the base times the height must equal 800
>80(x)=800
>x=10
800/2=400 so the base length is 10 cm.

Hopefully this helps?

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3 pencils in each package

It is scary to think that you may actually unironically totally seriously believe this.

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is r9k really this dumb

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EDUCATION SYSTEM IS FUCKED I LITERALLY DO NOT KNOW ANYTHING IT HAS FAILED ME AND EVREYONE ELSE

No, they solve it because they have the lesson and the equations right in front of them, and were likely told exactly how to a few minutes before the problem was given to them. It decays overtime, so most adults don't retain their math sense without continuing to study.

16 teams, 2 forwards and 5 guards per team.

this is really basic shit, user. i don't even remember when i learned this stuff

5 guards
this is basically identical to the last problem

these problems are based on insanely basic principles that ought to be burned into your mind if you finished high school. no one blames you for not being able to solve it as readily as a fifth grader might, but you should be able to figure it out.

>if you finished high school
damn I guess it all makes sense

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You're right, I wasn't actually looking at the last few that were posted

Alright, kids, let's keep this up.

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To find the length, devide area by width.
1600/80=20

Since the base of a pennant takes up half of the length of a side, its 10cm.

Give us something harder next time.

it had to be math
i fucking suck at math

>specialization in literally anything requires you know it
fuck this shit

>Give us something harder next time.
Ok, this one's just for you, sweetie.

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>at a given time, the value of the computer is decreasing at a rate that is proportional to the value of the computer
This is my attempt at rephrasing this sentence, and it's honestly incomprehensible to me what it means

No, i threw away that irrelevant shit because you arent meant yo remember how to do these equations 13 years later. Its just math thinking practice. If you know how to solve this its because its a part of your current curriculum in some uni class, or if it isnt, youve got no idea of what important things are and probably cant do much in the real world with such trivia oriented memory.

11 year olds would struggle for a month to do get their tiny brains around the idea of multiplication and dividing a few variables but they dont have to worry about forgetting the equation.

10 cm btw

It's been a long time since I solved for santa hat

fuck i haven't done calc 2/3 in a long while but i'll give it a shot
is it integral from 1 to 8 of the integral from 2 to 3 of log2(x) dx dy?

>If you know how to solve this its because its a part of your current curriculum in some uni class

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It's a triangular flag for sports teams

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nope i'm retarded and lookin it up, lemme try again

base * height * 0.5 = Area of a triangle

There are five triangles of the same size, hence 1600 / 5 = 320

base * height (80) * 0.5 = 320

base * 40 = 320

divide by 40 on both sides

The base of each penant is 8 centimeters long

you're welcome for help on your math homework.

nice skills bro, are going to please a woman with that :D fucking virgin kys

>simple division and multiplication
>abnormal skills

So the computer's value decreases at a certain rate each year.
850x^2=306
x^2=306/850
x=0.6
so 850(0.6)^5 = $66.01
Is that right? This one challenged me.

Let's do problems that are a little more fun to solve now, kids.

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i dont want to google old math equations just to show my dicksize to some random on the internet posting questions that rely upon knowledge everyones forgotten because theres nonreason to remember this unless your in specific careers. Just a waste of memory that can be ressurected easily when theres s need to, every dipshit in the thread can do math from their highschool level theybe just all forgotten the equations which is a google search away. T.bachelors in computer programming.

pi times the integral from 1 to 3 (2^y)^2-1 dy?

I'd do a step by step but nobody here gives a minor fuck. it's 10

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fuck it's been a few years since calc 2, i don't remember these off the top of my head. i could do them if i looked up the formulas but i really can't be bothered, these are actual work

So if the whole area is 1600cm2 that means a single pennant is 400cm2.

We need to find out the height of the base of the pennant so it's best to divided the isosceles triangle that forms the pennant into 2 so that we have 2 right angle triangles.

So, for one right angle triangle we have an area of 400/2 = 200cm2 and a height of 80cm.

So it should be (unknown) x 80 / 2 = 200

So the length of the unknown leg should be 5.

Since two right triangles make a pennant you multiply 5 x 2 to get 10.

The length of the base of the pennant is 10.

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>I can't do basic geometry b-but...!!!!

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Ah, you must like trivia then.

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how the fuck is that 80 if the area is 1600

If you flip a fair coin 444 times, what is the probability that you will get exactly 222 tails?

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If you flip a fair coin 4 times, what is the probabiIity that you will get exactly 2 tails?

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Whats your degree big boy? Is it STEM? Or just trying to specialize in 4th grader mathematics. I already told you theres no point in proving intelligence by making people ressurect typically useless information that they certainly know how to do.

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B*H = 1600
B=1600/H
(H/4)^2+80^2 = (1600/H)^2
real solutions for H are approx. +-19.961
base = H/2 = 19.961/2 = 9.9805

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There are 9 students in a class: 7 boys and 2 girls.

If the teacher picks a group of 3 at random, what is the probability that everyone in the group is a boy?

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0% chance

orignnnenal

i end up with a negative using pi*integral from 0-3 of (1/3x^2+4)^2-(x+4)^2 dx
what am i doing wrong

How do you determine that for every year x is squared?

The deprecation x is applied each year.
So the first year would be 850x = N.
The second year is Nx = (850x)x = 850x^2

you're all fucking retarded and the question is poorly written, your answer would be correct IF we're assuming that the area or each pennant are equal, it also doesn't say whether or not the height given is perpendicular to the base because if it not you can't use that formula, so if we assume both of those things are true (and I think we sort of can because the question would be impossible to solve otherwise) then your solution would be correct but it doesn't specify soooooooooooooo well never know

>you're all fucking retarded
You just got a free ticket for a boat ride, and you can bring along 2 friends! Unfortunately, you have 5 friends who want to come along.

How many different groups of friends could you take with you?

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about 42% rounded up

did you even read my reply? there isn't enough information to solve the question, it assumes too much, like that the areas are equal and the height is perpendicular to the base

Well, how many different groups of friends could you take with you?

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ill be taking you with me

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is it 5 choose 2?

It makes these assumptions because it's a math problem for children who haven't yet learned about their necessity. It's basic introductory geometry. In context, those things are given, because the problem would be unsolvable otherwise.

I learned this shit when I was in 6th grade, then swiftly forgot it.

Which is the problem with our educational system. If something you learn isn't relevant in your day to day life, you'll forget it. That's why we need to go back to the old system of apprenticeships.

All triangles seem equal size, so each triangle is 400 sq cm
Area = 1/2 x base x height
400 = 1/2 x b x 80
Base = 10 cm
Based