You will be working in a grocery store at 40 if you can't solve this

If you flip a fair coin 6 times, what is the probability that you will get exactly 2 tails?

Show all your work.

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bout tree fiddy

original answer

6 coins has the following possible outcomes
HHHHHH
HHHHHT
HHHHTH
...
TTTTTTT

That's 2^6 = 64 cases. But that's a lot to deal with and may not be helpful. The next question is how many of them have 2 and only 2 heads

HHTTTT
HTHTTT
HTTHTT
HTTTHT
HTTTTH

This pattern has 5 possibilities

(cont'd)

Hold on let me ask my store manager

Well if he works there it's because he, too, couldn't solve it so why ask him?

>durr

Now, let's look at the next smallest set
THHTTT
THTHTT
THTTHT
THTTTH

That's 4 possibilities. Next is

TTHHTT
TTHTHT
TTHTTH

That's 3 possibilities Next is

TTTHHT
TTTHTH

That's 2 possibilities. Next is just

TTTTHH

One possibility. So, in total we get 5+4+3+2+1 = 15 cases out of 64, which is about 23%?

I FUCKING HATE MATH

PLEASE TELL ME WHY IT'S IMPORTANT

WHAT THE FUCK IS THE POINT OF IT

HOW IS IT NOT FUCKING USELESS

PLEASE TELL ME

FUCK MATH

That's the joke you mouth breathing, in-bred retard.

It's thanks to math that you posted this on the internet using your computer.

Bruteforce method:
TTHHHH
THTHHH
THHTHH
THHHTH
THHHHT
HTTHHH
HTHTHH
HTHHTH
HTHHHT
HHTTHH
HHTHTH
HHTHHT
HHHTTH
HHHTHT
HHHHTT

Those are the possibilities for getting exactly 2 tails in 6 flips. If each row of 6 flips were equally probable, out of 2^6 possible cases, you'd get 15/64 probability, or about 23.44%.

>durr
As predicted.

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You are gay and maybe if you graduated high school before posting then you would be slightly less gay

Math is a meme
>be high school drop out going to community
>take multiple choice aptitude test that lets me into precalc
>bs and cheat my way through despite not even understanding algebra
>never have to take math again

2^6 = 64 total possible outcomes
6 choose 2 = 6*5/2 = 15 outcomes with exactly 2 tails
probability of exactly 2 tails = 15/64

2/6 = 30%. 30%/2= 13.6.
the answer is 15/64.

Math is like mental weightlifting. It makes you more able to think through problems more clearly.

Congratulations. So since you lads won't work in a grocery store at 40, what are you studying (if you didn't already start a career) and how are things going?

Total outcomes = P(2,6) with replacement = 2^6 = 64
Two tails = C(6,2) = 15
15/64
t. Just learned this in discrete math

Congrats you predicted you were mentally deficient.

If you are the same italian from the other thread, why is your language so garbage and why is Italy so bad at everything they ever do?

Another one:

There are 10 students in a class: 3 boys and 7 girls.

If the teacher picks a group of 3 at random, what is the probability that everyone in the group is a girl?

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>50080421
you sound like my 3rd grade math teacher hated that woman but okay
flipping a coin gives your a rough probability of 1/2 landing heads or tails. Depending on velocity it could be higher or lower so you could have a 1/4 of being heads or a 1/10000000000 chance of heads
really to be quite fair the number of possible outcomes is 64
64 divided by 6 is 10.666 recurring

so there thats my fucking best answer im in grade 9 and havent even gotten math yet so give me a break. Was I atleast close

>30%/2= 13.6.
Well, done, very nice. Still got the answer in the end.

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I'm in my 40s and working at a grocery store atm.

I predicted your sperging out.

I'm a software engineer. School was a decade ago.
While technically correct, brute forcing a problem like this is a bit cringey.
The correct answer has already been posted several times. You're not even close.

fuck I knew I was better at history. Well I still have time to fix this shit

Just use permutations and combinations, brainlets.

kek this math

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1.5?

original answer

l'll need 2 bags and also some orange tic-tacs.

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How's work?

ori

Total ways to choose 3 students = P(10,3) = 720
Total ways to choose 3 girls = C(7,3) = 35
35/720 = 0.0486
About a 5% chance.

Is this formula correct ?
N being the time we launch the coin (or any other object with P equal faces) ?
I could probably be wrong, just asking for your opinions on this (quick and dirty) search.
Please give me validation

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Oups, am stupid, meant to say P desired tails.
I though of a dice because of the six relaunch of the coin

this is originally quite wrong

asking a combinatorics problem is extremely retarded. Most people who aren't pure math majors never learn it. There are traces of it in statistics classes but only like 2 chapters. It's not really important to anything except comp sci. Even physics majors don't learn this.

it's just a bait thread, friendo

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They keep going back to gambling scenarios, but what's the point of knowing that getting a royal flush is unlikely to happen? At what point has anyone used what they learned in probability class to win at the casino? There were a group of statisticians that gamed a lottery to win like, half a million but you get paid more annually as some wall street bigshot. And even then we get it drilled into our heads that we can't game the stock market without illegal insider knowledge.

Easy.

(7/10)*(6/9)*(5/8)=29.2%.

Now, what's the story behind your pic? Looks amusing.

something / 10C3

Probability of landing on a specific combination: 0.5^6
>0.5 chance 6 times
Possible combinations with exactly 2 tails: 6*5 *1/2
>choose turn that you land on tails (6 of them), then choose turn you land on tails again (5 left), then choose all the heads (1 because it doesn't matter so there's only one way), then remove all the duplicates (1 duplicate because you can switch heads and tails for all choices)

Final answer: 15/64

I meant to say that you can switch the tails once for all the duplicates, not heads and tails.

I hate statistics and an user has already posted a similar answer but here. I would like to see an easier way to do it though

7/10 chance first picked is a girl
6/9 chance second girl
5/8 chance third girl

7/10 x 6/9 x 5/8 = 0.2911111
= 29.16% to 2dp

6 choose 2 = 6! / (2! * 4!) = 15 ways to rearrange 4 heads and 2 tails
2^6 = 64 total combiations
probability = 15/64

bump

fozsfeg

Alright i just got the answer

2^6 and 5+4+3+2+1 and divide 15/64
Its 23%.

At first i tried to simplfy by just doing 1 out 3. And geting 3/8 and just doubling it to compensate for 2/6 coins. But its not accurate because it doesnt take into account if you get the 2 coins in the first 3 instance and thats why i couldnt figure why my math was wrong.

100%

You shitbirds.

Mind you, normally heads is what it lands on.

There is no such thing as a fair coin.

This, i just did it. Flipped 6 coins and got 2 tails. So its 100% chance. Prove me wrong.

>Prove me wrong.
I just did it and my house caught on fire.

Exactly 2 heads can be placed (6 choose 2) ways for 15 cases. The probability of each case is 0.5^2+0.5^4 or simply 0.5^6 since H/T are equally probably.

Thus the probability of exactly 2 heads is (6 choose 2)*0.5^6 = 0.234375