Can you?
Can you?
4?
The answer is 9!
i don't know
i just want to die after this
desu this is a good post
After solving the gaussian integral which gives you sqrt(pi/a) you can treat all the wacky math symbols as variables and solve the system of equations. Hell you just need the second and fourth.
My head asplode.
Too many undefined variables.
OMG you're right it is 9
I don't know why you are the surprised!
No wait you're not right
Look again the formula on the bottom is not the same as the one on the top
It's -2
>negative
no
42
I don't even know what most of those fucking symbols mean
Gibe more info. Are there only natural numbers?
WHERE ARE THE NUMBERS
No
on the right lole
Just kidding by the way
Very quickly you notice the flaw that 1, the Reimann zeta function hasn't defined limits and 2, the final expression is the solution of the reimann zeta function so i believe the person who made this is a troll
Unironically 6, but you have to say that \zeta(s)=\sum_{n=1}^{\infty}\frac{1}{n^s}
Which is only true if Re(s)>1
1.- a+b+(c)(d)+e =12
2.- f+a+b =14
3.- e+a+b =3
4.- c+d+f =10
1 - 3 = 9 = (c)(d)
the answer is either 6 or -6
if (c)(d) is actually (c+d) then the answer is 9 like this guy says