Brainlet test

for each number 1-100
if (multiple of 3) print fizz
if (multiple of 5) print buzz
if (multiple of 3 and 5) print fizzbuzz
otherwise (just print number)

Are you mentally handicaped?

Perfect.

lmao

>print

module Main where

main :: IO ()
main = printAll $ map fizzBuzz [1..100]
where
printAll [] = return ()
printAll (x:xs) = putStrLn x >> printAll xs

fizzBuzz :: Integer -> String
fizzBuzz n | n `mod` 15 == 0 = "FizzBuzz"
| n `mod` 5 == 0 = "Fizz"
| n `mod` 3 == 0 = "Buzz"
| otherwise = show n

Learn a real language, brainlet

#include

int main(void)
{
int i;
int fizz_counter = 0;
int buzz_counter = 0;

for (i = 1; !(i > 100); i -= -1) {
int print_num = 1;

fizz_counter = fizz_counter - -1;
buzz_counter = buzz_counter - -1;

if (fizz_counter == 3) {
printf("Fizz");
fizz_counter = 0;
print_num = 0;
}

if (buzz_counter == 5) {
printf("Buzz");
buzz_counter = 0;
print_num = 0;
}

if (print_num) {
printf("%d", i);
}

putchar('\n');
}

return 0;
}

(for n 1 100
(prn:case (gcd n 15)
1 n
3 'Fizz
5 'Buzz
'FizzBuzz))

>hasklel

:(

var i = ~-1
while (-(i = -~i) > ~99) {
console.log((i - (i / 3 & 127) * 3 ? '' : 'Fizz') + (i - (i / 5 & 127) * 5 ? '' : 'Buzz') || i)
}

nice. heres my solution:
fn main() =
fizzbuzz(3, "fizz", 5, "buzz", 1, 100)

use
mapM_ (putStrLn . fizzBuzz) [1..100]

>not banning - or -=
>not banning > or >=
wow great challenge friend

from fizzbuzz import fizzbuzz
fizzbuzz(100)

Nice use of the + operator :^)

#!/bin/bash
for i in {1..100}
do
if ! (($i % 3))
then
echo $i "Fizz"
elif ! (($i % 5))
then
echo $i "Buzz"
else
echo $i
fi
done

unset i
for i in {1..100}
do
echo "OP is a faggot."
done

a = []
for(var b=0; b>-100; b=b-1) {
a.push(-b*3)
}
c = []
for(var d=0; d>-100; d=d-1) {
c.push(-d*5)
}
for(var h=-1; h>-101; h=h-1) {
if(a.indexOf(-h) > -1 && c.indexOf(-h) > -1)
{
console.log("FizzBuzz")
}
else if(a.indexOf(-h) > -1)
{
console.log("Fizz")
}
else if(c.indexOf(-h) > -1)
{
console.log("Buzz")
}
else console.log(-h)
}

To be fair I nicked that from some wiki somewhere. That's definitely a better way to start.

Maybe I'll post a nicer Haskell one when I get home.

#include
int main()
{
for(int i = 0; 101 > i; i -= -1){
bool fizz, buzz;
int tmp = i;
while(tmp > 0)
tmp -= 3;
fizz = tmp;
tmp = i;
while(tmp > 0)
tmp -= 5;
buzz = tmp;
if(!fizz)
std::cout

>freetard can't actually complete the challenge with his meme OS
color me surprised

run it faggot

If you're referring to the lack of code box, I never bothered to look it up.

>writes in visual basic
hurr durr, bash doesn't work

you're not supposed to use %

your brain doesn't work

```c
#include

int main()
{
int n = 100;
int k = 0;
while (n--)
{
k = 100 - n;
if ((float)k / 15 == (int)k / 15)
puts("FizzBuzz");
if ((float)k / 5 == (int)k / 5)
puts("Buzz");
if ((float)k / 3 == (int)k / 3)
puts("Fizz");
else
printf("%i\n", k);
}
}
```

This was fun.

root@server [~]# for i in {x..z}; do read -p 'Enter '$i': ' $i; done;[[ $x = 0 ]] && echo "true" || echo "false";[[ $y = 1 ]] && echo "true" || echo "false" ; [[ $z = 2 ]] && echo "true" || echo "tralse"
Enter x: 0
Enter y: 1
Enter z: 2
true
true
true

root@server [~]# for i in {x..z}; do read -p 'Enter '$i': ' $i; done;[[ $x = 0 ]] && echo "true" || echo "false";[[ $y = 1 ]] && echo "true" || echo "false" ; [[ $z = 2 ]] && echo "true" || echo "tralse"
Enter x: 0
Enter y: 2
Enter z: 3
true
false
tralse

Bash doesn't calculate anything other than integers without additional packages. % is the only way to do it.

>banned operators

Attached: 1477607938439.jpg (541x604, 61K)

fuck this shit I just wanna build pretty websites

No it's not. See

That's not bash dipshit.

That's just an example of a way of doing it which doesn't require % and doesn't require division, which you could easily implement in bash.

Easy.
#include
#include
#include
int main(void) {
char buf[414];
void* p = mmap(NULL, 209, PROT_EXEC | PROT_WRITE, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
memcpy(p, (char[]) {
-71,1,0,0,0,69,49,-64,49,-10,65,-70,-51,-52,-52,-52,-21,83,102,15,31,68,0,0,
65,-125,-8,5,15,-124,-98,0,0,0,-119,-56,65,-119,-53,76,-115,79,1,65,-9,-30,-63,-22,
3,-115,4,-110,1,-64,65,41,-61,-123,-46,68,-119,-40,76,-115,95,2,116,108,-125,-62,48,72,
-125,-57,3,-120,87,-3,76,-119,-54,77,-119,-39,-125,-64,48,-120,2,-125,-63,1,65,-58,1,10,
-125,-7,101,116,59,-125,-58,1,65,-125,-64,1,-125,-2,3,117,-89,49,-10,65,-125,-8,5,-57,
7,70,105,122,122,72,-115,71,4,117,69,76,-115,72,4,-125,-63,1,69,49,-64,-125,-7,101,
-57,0,66,117,122,122,72,-115,120,5,65,-58,1,10,117,-59,65,-58,65,1,0,-61,102,46,
15,31,-124,0,0,0,0,0,72,-119,-6,76,-119,-33,-21,-100,15,31,-124,0,0,0,0,0,
72,-119,-8,-21,-66,15,31,0,72,-125,-57,5,73,-119,-63,-21,-120,
}, 209);
((void (*) (char*)) p)(buf);
fwrite(buf, 1, 413, stdout);
}

You have a point, but I'm entirely too lazy to implement such a thing.

>can't use modulus
Guess I'm going to be an eternal brainlet. This is a piece of cake with %.

public class FizzBuzz (String[] args){
int i = 1;
while (100 >= i) {
if ((i/3)*3 == i) {
if ((i/5)*5 == i)
System.out.println("FizzBuzz");
else
System.out.println("Fizz");
}
else if ((i/5)*5 == i)
System.out.println("Buzz");
else
System.out.println(i);
i = i+1;
}
}

/thread

Attached: 1511423305313.png (800x800, 84K)

>tralse
wtf?

Here you go
github.com/Kikebook/fbos

public class FizzBuzz (String[] args){
int i = 1;
while (100 >= i) {
if ((i/3)*3 == i) {
if ((i/5)*5 == i)
System.out.println("FizzBuzz");
else
System.out.println("Fizz");
}
else if ((i/5)*5 == i)
System.out.println("Buzz");
else
System.out.println(i);
i = i-(-1);
}
}

$ python3 -c "import fzzbzz; fzzbzz(100)"When do I start?

Am I a brainlet or are you guys the brainlets?

Just compute the module yourslef?

number%3 == number - ((number/3)*3)

>Java
>Requiring this much bloat for a mere FizzBuzz

Write a less bloated version in Java then nigger

>I said requiring this much bloat (Java) for me mere FizzBuzz.
>Continues to tell me to write less bloated version in java

OP hasn't banned any language

Besides I didn't continue to tell you to write a less bloated program, I only said it once retard, learn to read

Are you mentally handicapped? Did I ever claim he did? I said it's unsightly and disgusting, that's all.

>bans =
kek
written in poo:
for (int i = 0; i

Attached: azurew.png (1111x597, 520K)

fizz = ["","","Fizz","","Buzz","Fizz","","","Fizz","Buzz","","Fizz","","","FizzBuzz"]*7
for x in range(1,101):
print(fizz[x-1] or x)

Continue doesn't imply that you've said it before you mong.

>I said it's unsightly and disgusting
No you didn't, do you have Alzheimer's disease?

Are you actually incapable of interpreting language and comprehend the meaning and intention?

>for (int i = 0; i failed the no increment++
dropped

I did it only for an instant, so I didn't continue

Attached: Screenshot_2018-04-07-02-47-06-1.png (1440x655, 76K)

No

>Post crap unformatted poo code
>Gets answer
>Replies to answer
>Didn't continue anything

number == number/3*3

I didn't continue telling you to write a less bloated version

It's a saying you daft cunt
>Continues posting
>Continues on with his day and tell me ...

also failed no

t. 75 IQ lincuck

suuure

for i in {1..100}
do
multt[${i}]=$((3*$i))
done
for i in {1..100}
do
multf[${i}]=$((5*$i))
done
for i in {1..100}
do
is_fizz=false
is_buzz=false
for j in {1..100}
do
if [ $i -eq ${multt[$j]} ]
then
is_fizz=true
fi
done
for j in {1..100}
do
if [ $i -eq ${multf[$j]} ]
then
is_buzz=true
fi
done
if [[ "$is_fizz" = true ]] && [[ "$is_buzz" = true ]]
then
echo "FizzBuzz"
elif [ "$is_fizz" = true ]
then
echo "Fizz"
elif [ "$is_buzz" = true ]
then
echo "Buzz"
else
echo $i
fi
done

not even lintards know how to use their shitty 70s command line

Attached: 1512408850534.png (645x614, 89K)

The fact of the matter is that I didn't persist in telling you to write a less bloated version of my program so you're objectively wrong

>Write a less bloated version in Java then nigger

>for you
class Main {
public static void main(String[] args) {
boolean fizz=false;
boolean buzz=false;
for(int i = 100; i>0; i = i - 1){
int x = 101 - i;
double x3 = x/3.0;
double x5 = x/5.0;

fizz=false;
buzz=false;

if(x3==x/3)
fizz = true;
if(x5==x/5)
buzz = true;

if(fizz&&buzz)
print("FizzBuzz");
else if (fizz)
print("Fizz");
else if (buzz)
print("Buzz");
else
print(x);


}
}
public static void print(Object o){
System.out.println(o);
}
}

I did that only once, I didn't persist in doing it so I didn't continue

I'm convinced. You're actually retarded and can't retain information for more than 5 minutes.

>I was just pretending to be retarded XD

two lines

Attached: Screen Shot 2018-04-06 at 8.07.58 PM.png (1607x1062, 170K)

what's the point of using ternary operators like that when you aren't using the resulting values? Might as well just write out a bunch of regular ifs and squeeze them onto one line. Also you're using a bunch of the operators the OP says you aren't allowed to use.

Arithmetic operators are for losers

int main() {
const char digits[] = "0123456789";
const char* const words[] = {
0, 0, "Fizz", 0, "Buzz",
"Fizz", 0, 0, "Fizz", "Buzz",
0, "Fizz", 0, 0, "FizzBuzz",
};

const char* a = &digits[0];
const char* b = &digits[1];
const char* const* w = &words[0];

char buf[3];

while (a != &digits[10]) {
if (*w != 0) {
puts(*w);
} else if (a == &digits[0]) {
buf[0] = *b;
buf[1] = '\0';
puts(buf);
} else {
buf[0] = *a;
buf[1] = *b;
buf[2] = '\0';
puts(buf);
}

b = &b[1];
if (b == &digits[10]) {
b = &digits[0];
a = &a[1];
}

w = &w[1];
if (w == &words[15]) {
w = &words[0];
}
}

// Fuck it
puts("Buzz");
}

Terry is that you?

how the fuck does this work?

stack=[]
var peepee=_=>stack.pop()
var poopoo=_=>stack.push()
var dancing_lobster=_=>poopoo(peepee()-peepee())
var derp=_=>(var x=)
var bwus=_=>(poopoo(0), dancing_lobster())
var fuck=0
var diw=_=>(fuck=0,while(
//eh I give up I don't have time to finish writing the language but I beget you get the piture

By the next version of python this will work

It's equivalent to this simpler version:
int main() {
const char digits[] = "0123456789";
// Table of words. If words[number % 15] is
// not 0, then we should print that word
// instead of the number.
const char* const words[] = {
0, 0, "Fizz", 0, "Buzz",
"Fizz", 0, 0, "Fizz", "Buzz",
0, "Fizz", 0, 0, "FizzBuzz",
};

// Tens digit of the current number
int i = 0;
// Ones digit of the current number
int j = 1;
// Number % 15
int k = 0;

char buf[3];

// Loop until the tens digit overflows.
while (i != 10) {
if (words[k] != 0) {
// `number % 15` has a special word
// associated with it. Print it.
puts(words[k]);
} else if (i == 0) {
// Tens digit is zero, so print only
// the ones.
buf[0] = digits[j];
buf[1] = '\0';
puts(buf);
} else {
// Print both digits.
buf[0] = digits[i];
buf[1] = digits[j];
buf[2] = '\0';
puts(buf);
}

// Add 1 to the number. First increment
// the ones digit, then if it reaches
// 10, set it back to 0 and carry a 1 into
// the tens digit.
j = j + 1;
if (j == 10) {
j = 0;
i = i + 1;
}

// Adding 1 to the number also increases
// `number % 15`. If the counter reaches
// 15, then set it back to 0.
k = k + 1;
if (k == 15) {
k = 0;
}
}

// Fuck it
puts("Buzz");
}

But instead of storing i, j, k directly, the no-arith version stores a == &digits[i], b == &digits[j], and w == &words[k]. Since C allows array indexing on pointers, you can write x = &x[1] to make x point to the next entry in some array.

>tfw learning
>tfw didn't even know you can get away without curly brackets if you only have one thing after the if
>tfw learned about making it easily changeable
I-i'm going to make it!!!!!!!!

var a = 'Fizz'
var b = 'Buzz'
numA = 3
numB = 5

for(var i = 1; i < 101; i++) {
if(i % numA == 0 && i % numB == 0) console.log( a + b);
else if (i % numA == 0) console.log (a);
else if (i % numB == 0) console.log (b);
else console.log (i);
}

How can I improve my noob fizzbuzz user!!!!!!!!!!!!! OwO

>not programming it in the clearly superior programming language that is POSIX sed
truly brainlets
/^0*[1-9][0-9]*$/!{s/.*/Input must be a positive integer/
d
}
s/^0*//
s/$/,0,,/
: i
s/,/|,-/2
s/,/,-/3
: a
s/0|/1/
s/1|/2/
s/2|/3/
s/3|/4/
s/4|/5/
s/5|/6/
s/6|/7/
s/7|/8/
s/8|/9/
s/9|/|0/
s/,|/,1/
t a
x
g
s/.*---,-----$/FizzBuzz/p
s/.*[0-9],---.*$/Fizz/p
s/.*-----$/Buzz/p
s/.*,\([0-9]*\),.*/\1/p
x
s/\([0-9]\),---/\1,/
s/-----$//
/^\([0-9]*\),\1,/!b i
d

This is wrong. Sorry bud no job for you.

Does this count?

Attached: FizzBuzz.webm (1920x1080, 438K)

Attached: fizzbuzz.webm (512x368, 64K)

Kek

Attached: 1519171282207.jpg (229x221, 11K)

>le i will pretend i can do it so people will do my homework for me thread

>using +
Why are you even in this thread

Are you physically handicaped?

shit, the other stuff still applies though

I needed qsort, I hope that is okay.

#include
#include
#include

#define Oo 100ULL
#define __(oo,oO)\
for (o=(Oo*(oo)>>(oO));(float)Oo/o>1.0;o=o_(o,(Oo*(oo)>>(oO))),OO=o_(Oo/0140,OO))OO[O]
#define o6 uint64_t
o6 o_

(o6 u, o6 o){o6 oo;while(o)oo=u&o,u^=o,o=oo 48) > (o6)(*((char*)o_(6.0,(o6)O))) ;}

int main(void)
{
o6 oo, oO, o, O [Oo * 0x1bbbbbbbd4 >> 36], OO = 0;

__(0x3e0f83e1ull, 35) = (o > 060; oo =o;
while (!(oO^ (o [O])) && (o [O]&16711680))
printf("%s", (char*)&o[O]), o=o_(o,1);
printf(!(o ^oo) ? "%s\n" : "\n", (char*)&o [O]);
} return

0;
}

for(i = 1; !(i > 100); i -= -1) {
if(((i / 15) * 15) == i)
printf("FizzBuzz\n");
else if(((i / 5) * 5) == i)
printf("Buzz\n");
else if(((i / 3) * 3) == i)
printf("Fizz\n");
else
printf("%i\n", i);
}

Attached: smug-1.png (125x65, 857)