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0.5^x = e^(log(0.5)*x)= e^(-log(2)*x)

is that a mating ritual of sorts

ye we gonna fuck now

Is there a way to do it without using the log function on your calculator?

you just write log(this) and log(that) in the answer, it usually is good enough without having to find the actual value (which you can't really do without a calc, yes)

God I wish that was me

oi good evening spain

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Yes you can approximate it with a reinman sum

Good evening lad
Back from Germany eh?

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And how would one go about doing so?

yeah was pretty fun, also pic i posted was accidently eh
wanna see a pic of me and friends watching animu on a projector at the train station?

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Yeah, sounds fun
What did you watch?
Also do you live close to the border?

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math.stackexchange.com/questions/977586/is-there-an-approximation-to-the-natural-log-function-at-large-values

yeah, zurich, big city. It took quite some time though because we went to the middle of germany.
we watched nichijou, because it was one of the only animes my friend had on his laptop back then, we didn't have any mobile data to download anything.
two of us (in the pic) were drunk and the guy who took the pic and made the projector ready was clean.
me on the left

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the lamp on the left side of the building was annoying for the projection so the other drunk guy had the idea to use his pants to dim the light

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the riemann sum shit is clearly not what he needs
look at the OP pic, it's not like they'd task him with adding up a series if he's doing something so simple

Oh cool, I know a family who lives in Zurich as well, father's an architect
And the projector looks lit af desu, is Nichijou fun?

Also you look smol in the pic ;^)

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not series, dammit. the other thing. i learned english from shitposting, so my math terminology fails me

base

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yeah, it was fun
but also damn cold
the jägermeister helped though

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I have mixed opinions on jäger, whiskey and vodka are my favourite liquors honestly
But rum is the best for cold nights

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X is 0,58

>1,5 x 0,5^X = 1 | :1,5
>0,5^X = 0,66
>Log (0,66) = -0,18; Log (0,5) = -0,30
>-0,18 : -0,30 = 0,5849625

If you have a good calculator and you only want the result, there's often an equation function you can use. Just enter the equation and it gives you what you want.

comfy as fuck

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I love jäger and whiskey, big fan. Drinking rum usually on coke and no fan of vodka.

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Do you know Schierker Feuerstein?
It's basically Jägermeister but better imo, I can really recommend it.

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I don’t think this user should be worried about that if he needs help finding x here

i'll look out for it next time i visit the liquor store!

Ok I can comprehend this but is there a way to solve it without Log (since I don't quite have a good grasp of it).

The only other way I know is grind and try out numbers, but since we're not dealing with integers here, that would take a while.
Log is the only sensible way there is to figure stuff like that out.
If you're not supposed to use calculators, is as close as you can get.

You can simplify it a little bit if you like but you're pretty much stuck with the log.

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BUT IN THIS SCUFFED FUCKING BOOK LOG IS INTRODUCED AFTER THIS! HOW ARE YOU SUPPOSED TO SOLVE THIS IF YOU DON'T KNOW ABOUT THE LOG FUNCTION!

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That's kinda weird. It seems very obvious from the choice of numbers that it's an exercise specifically designed to train you in simplifying log expressions

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