is Jow Forums smart enough for this simple little thing?
1, 6, 8, 10
what are the following numbers and why? (if you do not explain how you got to the answer, it will be ignored).
is Jow Forums smart enough for this simple little thing?
1, 6, 8, 10
what are the following numbers and why? (if you do not explain how you got to the answer, it will be ignored).
Other urls found in this thread:
mathworld.wolfram.com
oeis.org
oeis.org
twitter.com
The next number must be larger than the previous one.
They are all positive integers.
how much larger exactly? you need to give an exact number (or two)
14
15
multiplicatively perfect numbers
At least 1. Possibly 2.
They're 1(one), 6(six), 8(eight) and 10(ten), because they are numbers
Any amount as long as it's larger
OMG MATH XD
wrong.
12, 14, 16, 18..
fuck off pseudo-intellectual
>following numbers
meaning the numbers following (after) the numbers above
Prove it. The rule fits.
now the explanation
Trick question, there are no following numbers in the post, only preceding numbers. The following numbers are 67831686, and I got them by looking below the question.
Here's how to solve this:
1. Think for a second, does it look obvious?
2. Decide not to waste any more time on it and consult the OEIS
3. oeis.org
4. Problem solved.
15. 26, 46, 78
Explanation: we're looking for a, b, c, d such that ax^3 + bx^2 + cx + d equals 1 for x = 1, 6 for x = 2, 8 for x = 3, and 10 for x = 4. If we solve it using wolframalpha, we get some numbers that I'm too lazy to copy paste here so I'll just include a screenshot, and then using wolframalpha in another tab, we can substitute in 5, 6, 7, ... for x to get the next numbers in the sequence.
about this many
Based but you can do better, by leaving out steps 1 and 2
>OP ignoring correct answers
>oeis.org
multiple answers, the right one among them, but you don't win because your answer is not specific.
OP here, winrar
What am I supposed to do? Guess until I find the "right" answer? You've not provided enough information to deduce which one is right.
Am I a genus for figuring it out without ever knowing about the perfect multiplicative numbers anons posted about
+5 +2 +2
protip: you can't prove me wrong
>if you cannot identify this sequence of 4 integers, you are a brainlet
t. brainlet
092818
Those are the following numbers.
Just scroll down.
*fort-nite dance*
Too easy.
-posted from my ipad using on-screen-keyboard
12, 14, 15, 18, ...
>Numbers n where total number of 1-bits in the exponents of their prime factorization is even
Winner
Actually, I can provably enumerate an infinite number of rules which would fit this scheme. I take it you haven't taken much CS.