2-3*2=?

4294967292

4!

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someone with High iq would place braces so the equation isn't ambiguous.

this way it can be -4 which you most likely meant but it can be invalid aswell if talking about Harvard level math

>2-3*2=?
>2-6=?
>4=?

-4=?

P
E
MD (left to right)
AS (left to right)

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-4 is the only correct answer.

>what are imaginary numbers

-4 = 4*(i^2)

underrated

-4

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>someone with High iq would place braces so the equation isn't ambiguous.
Nigga they teach pemdas in elementary school, ambiguous my ass

>2 3 2 * -
>2 6 -
>-4

Ok? You're trying to be pedantic, I know, but you just look retarded instead.

You don't ACTUALLY understand what imaginary numbers ARE, do you?

It's -4

>someone with High iq would place braces so the equation isn't ambiguous.
((((((((3+3)+3)+3)+3+3)+(3+3)+3)+3)+3)+3)
Yes. Clearly this is the less ambigious way to do any kind of math.
>this way it can be -4
It can "Only" be -4
In the case of 2 - 3*2 it will always equal -4
In the invalid case of 2 + (-3*2) it would still be -4

>>what are imaginary numbers
All in your head.

eval(2-3*2)
-4

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Though really belongs in the > the answer, by the way, is -4

T. Materialistic relativist

>Picrel
Isn't that too simple?
You could just write 6 + 1*2 - 1 + 1 for every equation. Or no new numbers as in, none at all, only 1 1 1 = 6 somehow.

>6 + 1*2 - 1 + 1
I meant 6 + 1*2 - 1 - 1
That solves correctly.

wrong the last case is invalid meaning it cannot produce a result. that is why he has to add the brackets else it isnt an equation but just some signs and numbers

yeah thats what is said

>In the invalid case of 2 + (-3*2)
>wrong the last case is invalid
??

>that is why he[OP?] has to add the brackets
No, that IS a valid equation

You're a retard

>6 + 1*2 - 1 + 1 for every equation

>1. You cannot introduce any new digits

>Imagine somebody on Jow Forums actually believing this

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>Imagine knowing how stupid people are

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2-6 is fucking -4 you faggots its -6 + 2 you fucking idiot faggots its -4

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-2

Trick question, you can't multiply by 0

I'm confused, is (0! + 0! + 0!)! Allowed?

Do they violate the listed rules?

(1+1+1)!

-4

-4.0000000000000000000000000000000001

It must be otherwise the 000 one is undoable

Lol'd

(0!+0!+0!)!
(1+1+1)!
2+2+2
3+sqrt(3*3)
(4!/sqrt(4))/sqrt(4)
5+5/5
6*6/6
7-(7/7)
8-sqrt(sqrt(8+8))
9-sqrt(sqrt(9*9))
sqrt(10-10/10)!
what do i win

A nice, warm cock. Ass or mouth?

(0!+0!+0!)!
(1+1+1)!
2+2+2
3! +(3-3)
sqrt(4)+sqrt(4)+sqrt(4)
5+(5/5)
6+6-6
7-(7/7)
8-sqrt(sqrt(8+8))
sqrt(9)! + (9-9)
sqrt(10-(10/10))!

negative four

4 is a power of 2 idiot

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