>If you use 8 characters and you choose from alphanumeric characters (A-Za-z0-9) there are (26+26+10)^8 = 62^8 = 218340105584896 possible combinations, against a GPU with 130 million tripcodes per second it will take about 19.4 days running non-stop to exhaust the keyspace.
You know the DES tripcode is 10 characters and not 8 right?
Dominic Bennett
Then it would be just 62^10 instead. Not a big deal.
Charles Martin
But what’s the hash algorithm?
Jackson Moore
It would require more disk space than there are atoms in the universe
Luke Ortiz
hmm yes, 20 days times 62 and 62 again is 210 years.
Henry Ross
>62^8 vs 62^10 >not a big deal user...
Gabriel Baker
>GPU with 130 million hashes a second >roughly 74724 DAYS >>NOT A BIG DEAL
Isaac Howard
With 1000 computers dividing the work evenly that's 2.5 months
Evan Sullivan
Ahh yes, rent 1000 GPUs for 2.5 months just to find that one tripcode. Then the tripfags switches to SHA-1 12 character tripcodes and all your work is ruined.