Jow Forums literacy test

How smart are you Jow Forums?

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r = sqrt(a2 + b2)
a = r - 2
b = r - 4
r = sqrt( (r-2)^2 + (r-4)^2)
solve for r

10

So...what is r?

jesus christ...
r = sqrt( 2*r^2 - 12r + 20 )
=> r^2 = 2*r^2 - 12r + 20
r^2 - 12r + 20 = 0
r = 6 +/- 4, 10 or 2

4 is out of scope as then b would be 0 and no rectangle would be formed, so it's
r=10

>doing the underage faggot's homework for him

*holds up finger to 4*
*moves finger down circle*
It's about 10

No way to tell. It's two circle segments, they could have different dimensions.

everyone falling for the math meme, lmao u guys are retarded, just take a measureing device put on screen see what 4 and 2 represents and just measure the fuckign radius in 2 seconds, smartasses lmao

10 is correct

High school geometry/trig isn't the best indicator of intelligence...

5,5

that's easy
r = 10

Aye but is a good brainlet identifier

Using foil in reverse I get 10 or 2, but I've never seen someone get an answer like "n +/- x". What method gives an answer like that? From the last equation?

>r^2 - 12r + 20 = 0

That one being the "last equation"

R=10

Oh boy, i miss math, i knew I should have done engineering.

there is a rule you learn in 8th grade or so
if you have
x^2 + px + q = 0
the two solutions are
x = -p/2 +/- sqrt[(p/2)^2 - q]

Thanks

I made it through calc 2 and I've never seen it done like that.

If you had:
2x^2 + px + q = 0

Would it then be:
2x = -p/2 +/- sqrt[(p/2)^2 - q]
?