Let’s test Jow Forums Hard mode

Ok the non brainlets got the first one.

Now this one,

50 LINK For the first correct solution.

Leave an address

Attached: E8B9C830-287C-435B-BF74-66B69DB8CE29.jpg (1125x986, 249K)

Other urls found in this thread:

mathwords.com/a/arc_length_of_a_curve.htm
physics.stackexchange.com/questions/288824/maximum-trajectory-length
wolframalpha.com/input/?i=integrate sqrt((cos a)^2 + t^2*g^2+2*t*g*(cos(0.5*pi-a))+(cos(0.5pi-a))^2) dt from 0 to (2/g*cos(0.5pi-a))
wolframalpha.com/input/?i=integrate sqrt((cos a)^2 +(cos(0.5pi-a)-t*g)^2) dt from 0 to (2/g*cos(0.5pi-a))
twitter.com/NSFWRedditVideo

>Doing this niggers homework

And no it’s not horizontal distance

45 degrees for that perfect sin curve.

See

I aint doing calculus for you nigga

56 degrees

Straight up 90 degrees yo

Exact solution

>maximum distance in the air

Literally 90° if maximizing air distance is the goal, questions wording is retarded though doesn't specify which direction air distance is to be maximized

If you just wanna maximize air DISTANCE, ie direction doesn't matter then fire it straight up