Let’s test Jow Forums Hard mode

Ok the non brainlets got the first one.

Now this one,

50 LINK For the first correct solution.

Leave an address

Attached: E8B9C830-287C-435B-BF74-66B69DB8CE29.jpg (1125x986, 249K)

Other urls found in this thread:

mathwords.com/a/arc_length_of_a_curve.htm
physics.stackexchange.com/questions/288824/maximum-trajectory-length
wolframalpha.com/input/?i=integrate sqrt((cos a)^2 + t^2*g^2+2*t*g*(cos(0.5*pi-a))+(cos(0.5pi-a))^2) dt from 0 to (2/g*cos(0.5pi-a))
wolframalpha.com/input/?i=integrate sqrt((cos a)^2 +(cos(0.5pi-a)-t*g)^2) dt from 0 to (2/g*cos(0.5pi-a))
twitter.com/NSFWRedditVideo

>Doing this niggers homework

And no it’s not horizontal distance

45 degrees for that perfect sin curve.

See

I aint doing calculus for you nigga

56 degrees

Straight up 90 degrees yo

Exact solution

>maximum distance in the air

Literally 90° if maximizing air distance is the goal, questions wording is retarded though doesn't specify which direction air distance is to be maximized

If you just wanna maximize air DISTANCE, ie direction doesn't matter then fire it straight up

how did you edit your post? trip?

Mod
>god

No, because then all the force is being used against gravity, remember we are neglecting air resistance

45 degrees. What a retard, everyone knows that since before high school.

Not horizontal distance
Flight path

alright then, 0.000000000000etc1 degrees

Fire 360°. Walk away.

180°

Kys.

>neglecting air resistance

nrm then, with nothing impeding the horizontal travelling force then yeah it'll be an angle less than 90° to maximize air distance

Wouldn't you also need the shape/weight/velocity of the projectile?

R=v0^2sin2θ0 /g

air resistance 35 deg
no air resistance: 45gef

>what are variables?
Fuck me, Jow Forums is retarded. How are you investing if you don't understand basic math?

56.4658

If I won then you can make a donation to the society of St Vincent de Paul.

Thanks

(the angle should be from the centre of the bore of the cannon to the horizontal)

You want to find what the maximum of x + y could be. If you fired it straight up, x would be 0

Actually I change my mind OP is interpreting the question wrong. Teacher just doesn't want you to include the projectile bouncing

This IS the angle that will give the longest trajectory.

Bonus points for latex?

I'm from a third world so pls no bully

0x3faa042d0e9fbeaef324f5b158831f8bc7351f24

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wow brainlet trying to shit on other brainlet
>Neglect air resistance

From where do you derive the first formula ?

damn yall are dumb fucking niggers couldn't even use google
mathwords.com/a/arc_length_of_a_curve.htm

It's not particularly basic to be honest with you. I'm a grad engineer and into ballistics so I could just use the correct terms to find the anger in a search. I don't thing its with in the math of the average person doing applied math at 18. Just a notch above. First year undergrad level

here

physics.stackexchange.com/questions/288824/maximum-trajectory-length

I bet OP having them cold sweats right

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Well OP?
>56.4658

what the fuck are you talking about? Weight and shape of the flying object is irrelevant. I hope you were answering someone else, or I fear you will not make it.

Let me quote that again
>Neglect air resistance

LITERALLY MAKE A FUNCTION AND SOLVE IT BRAINLETTE

Just realised OP very clever. I hear and understand

I tried solving this unlike the other brainlets, and we end up having to solve an equation which inbolves both polynomial terms in x and terms with arcsinh(x).

There is probably no analytical solution to this equation, so fuck you OP

48

Just noticed this post, as you can see we cannot solve this problem analytically

That does neglect air resistance otherwise you would need to supply the ballistic coefficient of the projectile. This also assumes a smoothbore cannon

>t. brainlet nigger

I wrote a math report about this in high school. Forgot the formula though.. Probably straight up / 90 degrees.

>no gravitational acceleration

shouldn't it never touch the ground again once it's fired as long as it points upwards

Bout tree fidty

got as far to make wolfram alpha timeout
wolframalpha.com/input/?i=integrate sqrt((cos a)^2 + t^2*g^2+2*t*g*(cos(0.5*pi-a))+(cos(0.5pi-a))^2) dt from 0 to (2/g*cos(0.5pi-a))

>Just noticed this post, as you can see we cannot solve this problem analytically

Meh. I could ( readily I have a ballistic calc on my phone). The fact is that the question is a basic formulaic one with little real application as the canon is unrifled.unknown (we would need to know the twist rate and barrel length), there is no BC, we have no air density, temperature, altitude, if we are being accurate the powder burn temperature, the muzzle velocity, the weight of the projectile in grains and the projectile diameter the latitude and longitude, compass direction of muzzle, the height of the cannon chassis above ground etc etc .

Ask a textbook question and get a textbook answer, which I gave you correctly here

>56.4658

and since I am not a liar I highlighted that here.
Do did not tell me I had to solve it from first principles and the full formula to solve it is as cited.

oh nvm i read it wrong

>remember we are neglecting air resistance
Creatura physics

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Just take a number of line integrals along different trajectories