What is the area

more importantly, is it a perfect dab?

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more than 21

but less than 22

27.9508497187

21.65

Let x be the horizontal axis, y the vertical
x' - value of x at which y = 0
y(0) = 5
y(x') = 0
x' = sqrt(10^2 - 5^2) = sqrt(75) = 8.6602

Now, as we know, any line can be expressed as y = mx+b

b = 5
8.6602×m = -5
m = -0.5774
y = -0.5774x + 5

Now finding the area is trivial, all we've got to do is take the definite integral of y(x) (x = 0; x = 8.6602)
Intg(-0.5774x + 5) = Intg(5) - 0.5774Intg(x) = 5x - 0.2887x^2. Inserting the values of x we get (5*8.6602 - 0.2887*(8.6602^2)) = 21.6488

A=(25√3)/2

You have to do Pywewean theorem

21,65

21,6

find te base wit pitagoras ten maket it basex5/2
21,6

In complez analysis, the general formula for Pythagorean theorem is the square of the magnitude of the sides instead of the square of the side. In other words, the hypotenuse is the square root of two.

21.5cm^2

It’s half times length times height

but you don't know the height, mutt

The hypotenuse wouldn’t be equal to the sidelength.

>0 length

Meme mathematics

but the length is not 0

i has a magnitude of 1

That’s why you use the Pythagorean theorem to find it, dummy

you didn't say that, though.

The hypotenuse is zero, which has no magnitude.

You must be trolling

some shit idk...

the hypotenuse is -1 + i, which is a complex number with a magnitude of sqrt(2)

I also didn’t call you a retard, but some things are a given.

Not in math they're not, retard.

>not enough info
but the op doesn't say it has a right angle, so it could be a triangle like this

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In this instance it’s pretty fucking obvious what you need to do in order to get the other sidelength.

It’s only unclear if you’re mathematically illiterate.

We have to assume it's a right angled triangle other wise the question is unanswerable.

you can find the angle x between 5 and 10 in paint and do the 25*sinx

5√125/2

>unanswerable
that's a trick of this question, so you can show the range of the area from the given condition (2 given lengths in this case)
anybody who assumed it's right angled triangle will fail in the exam

>being this proud of primary school geometry knowledge
lmaoing at your lyf, gonzalez

regardless, I know and you know that I know that you didn't notice the fact that the height is not given at first. You will vehemently deny this, of course, but it's true, and will remain true until the end of time.

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>I'll just put those arbitrary illogical rules so my precious math doesn't fall apart
>btw disregard the fact that imaginary distances actually exist in reality, specifically Minkowski Space and Imaginary Time
>also btw you cant divide by zero because I say so lmao

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>put those arbitrary illogical rules
It's called an axiom, buddy. Math (and any other flavour of logical system) is constructed entirely of them.

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>some shit idk...

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now that i look at it, there is no aliasing on the crossing lines so we can say they are perpendicular, thus the area is 25*sqrt(3), which is approx 21.6506

don't be so harsh on him, he's brown so you can't expect him to be on the same level intellectually

Why are you so angry and ignorant in this whole thread? Oh wait, flag.

>It's called an axiom, buddy. Math (and any other flavour of logical system) is constructed entirely of them.

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Math is flawed by design. Shan't be participating in this thread.

Find r.
If you can't solve this within a few minutes you're legit retarded

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25cm^2 innit

you know the side length of the square, so you know the diagonal length of the square, so subtract the big circle's diameter from the diagonal and divide by 4

more like if you can't solve within 30 seconds you're retarded

>1534461816172.jpg
>>It's called an axiom, buddy. Math (and any other flavour of logical system) is constructed entirely of them.

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>design

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and you're wrong lel
retard confirmed

assuming it's a square and those are two circles, r should be 3-sqrt8

math is stoopid

sqrt(50) or 5sqrt(2)

The radius doesn't go all the way to the edge. The result of your post is ((2+(sqrt(2)-1))*r)/2

retard confirmed, my method is 100% correct

All this stupid people who don't know how to math,first world is a fucking failure ,end this dumb earth

(sqrt(2)-1)/2

Is it the solution to the following equation?
2*(1-r)^2 = (1+r)^2

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int is more stupid than i thought, lamao

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...

Assuming turkman is right (3-sqrt8), looks like this answer is right :D

ijk

u r retarded

congratulations you're not retarded

If this solution requires knowing an equation and can’t be solved through some other intuition then it’s not indicative of intelligence. It’s just plugging in numbers

3-2sqrt(2) ???

p=(a+b+c) / 2;
r=sqrt( (p-a)(p-b)(p-c) ) / p;
r=sqrt( 0,5 / 0,5 );
r=1
Hence, R = r.

no it's

Hahahaha retard detected

1

Peasants

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Ugh... for real?

a2+b2=c2 so a=5*sqrt(3)

So P=a*h/2= 25*sqrt(3)/2 cm2

Intelligence is required to come up with the equation you moron. Are you still in fucking middle school?

Is this autism

I don't know, are you?

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A=b*h/2
h=5
b=?
r=10
h^2+b^2=r^2
5^2+b^2=10^2
b^2=100-25
b^2=75
b=8.66
A=8.66*5/2
A=21.65

I hope this is not wrong. It would be a very shameful display.

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are you blind? the height is 5. it is the length that is not given.

5 can be both length and height, depends where you look at it from.

How old?

it really doesn't matter, brainlet

my point is that you don't know one of the perpendicular dimensions

based

>math
lmao, now here's a REAL problem

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Last I night I James Bond burger your sister?

I have no clue I’m a brainlet god please fucking kill me

5^+x^2=10^2

x= sqrt(10^2-5^2)

x*5*0.5=area (cm)

okay how the fuck do you do this
I haven't done any math in like 3 years

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how the greeks have fallen

oh okay I get it now, thanks

2^.5*(1-r)-r=1
2.4142r=.4142
r=.17156

Between Q and S

(0.10m)^2=(0.05m)^2+x^2
-->
x=0.0866m

A=0.5*0.866m*0.05m=0.002165 m^2

R=1
R+r+sqrt(2*r^2)=sqrt(2)
--->
r=3-2*sqrt(2)=0.171573

pythagoreon theorum and then .5 times the width and height

>m^2
convert to sq in please